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Assoli18 [71]
3 years ago
7

Nancy winter local zoo that featured 11 monkey exhibits if these monkey exhibit make up 55% of the zoo exhibits then how many ex

hibits does the zoo have until the round your answer to the nearest whole number if necessary​
Mathematics
1 answer:
NeTakaya3 years ago
4 0

Answer:

20 total exhibits at the zoo

Step-by-step explanation:

55% of 20 = 11 (monkeys)

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This calculator will first reduce the improper fraction to lowest terms by dividing numerator and denominator by the greatest common factor (GCF). The GCF of 45 and 10 is 5. The remainder is 1. With 1 as the numerator and 2 as the reduced denominator, the fraction part of the mixed number is 1/2.
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What is the surface area of the right cone below?<br>​
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Answer:

54 is anwer.

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3 years ago
Suppose small aircraft arrive at a certain airport according to a Poisson process with rate α = 8 per hour, so that the number o
Ksenya-84 [330]

Answer:

Step-by-step explanation:

Step1:

We have Suppose small aircraft arrive at a certain airport according to a Poisson process with rate α =8 per hour, so that the number of arrivals during a time period of t hours is a Poisson rv with parameter μ = 8t

Step2:

Let “X” the number of small aircraft that arrive during time t and it follows poisson distribution parameter “”

The probability mass function of poisson distribution is given by

P(X) = , x = 0,1,2,3,...,n.

Where, μ(mean of the poisson distribution)

a).

Given that time period t = 1hr.

Then,μ = 8t

             = 8(1)

             = 8

Now,

The probability that exactly 6 small aircraft arrive during a 1-hour period is given by

P(exactly 6 small aircraft arrive during a 1-hour period) = P(X = 6)

Consider,

P(X = 6) =  

              =  

              =  

              = 0.1219.

Therefore,The probability that exactly 6 small aircraft arrive during a 1-hour period is 0.1219.

1).P(At least 6) = P(X 6)

Consider,

P(X 6) = 1 - P(X5)

                = 1 - {+++++}

                = 1 - (){+++++}

                = 1 - (0.000335){+++++}

                = 1 - (0.000335){1+8+32+85.34+170.67+273.07}

                = 1 - (0.000335){570.08}

                = 1 - 0.1909

                = 0.8090.

Therefore, the probability that at least 6 small aircraft arrive during a 1-hour period is 0.8090.

2).P(At least 10) = P(X 10)

Consider,

P(X 10) = 1 - P(X9)

                 = 1 - {+++++

5 0
3 years ago
Please help me for the brainliest answer
Oxana [17]

Answer:

aₙ= -2n²

Step-by-step explanation:

<h2><u>Solution 1:</u></h2>

The sequence:

  • -2, -8, -18, -32, -50

The difference between the terms:

  • -6, -10, -14, -18
  • a₁= -2
  • a₂= a₁ - 6 = a₁ - 2*3= a₁- 2*(2²-1)
  • a₃= a₂ - 10 = a₁ - 16= a₁ - 2*8= a₁ - 2*(3²-1)
  • a₄= a₃- 14= a₁ - 30= a₁ - 2*15= a₁ - 2*(4² -1)
  • ...
  • aₙ= a₁ -2*(n²-1)= -2 -2n² +2= -2n²

As per above, the nth term is: aₙ= -2n²

<h2><u /></h2><h2><u>Solution 2</u></h2>

The sequence:

  • -2, -8, -18, -32, -50
  • -2*1, -2*4, - 2*9, -2*25
  • -2*1², -2*2², -2*3², -2*4², -2*5², ..., -2*n²
  • aₙ= -2n²
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3 years ago
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jek_recluse [69]

Answer:

525 I think correct me if im wrong

Step-by-step explanation:

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