16 because 2•0 is 0. 8-0 is 8 and 2(8) is 16
Given that the length of one leg is 6 and the angle is 40°
The hypotenuse is x.
We need to determine the value of x.
<u>Value of x:</u>
The value of x can be determined using the trigonometric ratio.
Thus, we have;
![cos \ \theta=\frac{adj}{hyp}](https://tex.z-dn.net/?f=cos%20%5C%20%5Ctheta%3D%5Cfrac%7Badj%7D%7Bhyp%7D)
Substituting the values, we get;
![cos \ 45^{\circ}=\frac{6}{x}](https://tex.z-dn.net/?f=cos%20%5C%2045%5E%7B%5Ccirc%7D%3D%5Cfrac%7B6%7D%7Bx%7D)
Simplifying, we have;
![x=\frac{6}{cos \ 45^{\circ}}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B6%7D%7Bcos%20%5C%2045%5E%7B%5Ccirc%7D%7D)
![x=\frac{6}{0.766}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B6%7D%7B0.766%7D)
Dividing, we get;
![x\approx7.83](https://tex.z-dn.net/?f=x%5Capprox7.83)
Therefore, the value of x is 7.83(app.)
Hence, Option A is the correct answer.
Let x represent the number of ounces of vinegar
Let y represent the number of ounces of lemon juice
Oil required = 8 oz
Container can hold = 16 oz
So the inequality equation will be :
![x+y+8\geq16](https://tex.z-dn.net/?f=x%2By%2B8%5Cgeq16)
There are
![\dbinom62](https://tex.z-dn.net/?f=%5Cdbinom62)
ways of selecting two of the six blocks at random. The probability that one of them contains an error is
![\dfrac{\dbinom11\dbinom51}{\dbinom62}=\dfrac5{15}=\dfrac13](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cdbinom11%5Cdbinom51%7D%7B%5Cdbinom62%7D%3D%5Cdfrac5%7B15%7D%3D%5Cdfrac13)
So
![X](https://tex.z-dn.net/?f=X)
has probability mass function
![f_X(x)=\begin{cases}\dfrac13&\text{for }x=1\\\\\dfrac23&\text{for }x=0\end{cases}](https://tex.z-dn.net/?f=f_X%28x%29%3D%5Cbegin%7Bcases%7D%5Cdfrac13%26%5Ctext%7Bfor%20%7Dx%3D1%5C%5C%5C%5C%5Cdfrac23%26%5Ctext%7Bfor%20%7Dx%3D0%5Cend%7Bcases%7D)
These are the only two cases since there is only one error known to exist in the code; any two blocks of code chosen at random must either contain the error or not.
The expected value of finding an error is then
Answer:
w = x/50% = x/50/100
Step-by-step explanation:
We would turn the above question into an algebraic expression using variables.
To make a sugar syrup, we need sugar and water to form the solution.
Amount of sugar = x gram
Let amount of water = w gram
Sugar syrup solution = 50%
Sugar syrup solution = (amount of sugar)/(amount of water) × 100
50% = x/w × 100%
50% = x/w
Making w subject formula
w = x/50%
w = x/50/100