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tamaranim1 [39]
2 years ago
12

Problem 5

Mathematics
1 answer:
ddd [48]2 years ago
3 0

Answer:

100000000.09068588606047357608487007037864776060797704ww

Step-by-step explanation:

it is on gole

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Gloomy toothpaste comes in two sizes 9 ounces for $0.89 and 12 ounces for $1.15. Which size tube is the better buy?
sukhopar [10]
The 9 ounce toothpaste is a better deal.
I hope this helps you.
4 0
2 years ago
Pls someone find the answer to this question...i have exam tomorrow​
s2008m [1.1K]

Answer: 29.2cm

Step-by-step explanation: perimeter of parallelogram; 2(a + b) where a = base, b = altitude

a = 8cm

b = 6.6cm

Perimeter = 2(8 + 6.6) = 2(14.6)

Perimeter = 29.2cm

8 0
2 years ago
Please help me!!!!! :)
lora16 [44]

6 / (x + 6) = 10/15

10(x+6) = 90

10x + 60 = 90

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7 0
3 years ago
Consider functions of the form f(x)=a^x for various values of a. In particular, choose a sequence of values of a that converges
sleet_krkn [62]

Answer:

A. As "a"⇒e, the function f(x)=aˣ tends to be its derivative.

Step-by-step explanation:

A. To show the stretched relation between the fact that "a"⇒e and the derivatives of the function, let´s differentiate f(x) without a value for "a" (leaving it as a constant):

f(x)=a^{x}\\ f'(x)=a^xln(a)

The process will help us to understand what is happening, at first we rewrite the function:

f(x)=a^x\\ f(x)=e^{ln(a^x)}\\ f(x)=e^{xln(a)}\\

And then, we use the chain rule to differentiate:

f'(x)=e^{xln(a)}ln(a)\\ f'(x)=a^xln(a)

Notice the only difference between f(x) and its derivative is the new factor ln(a). But we know  that ln(e)=1, this tell us that as "a"⇒e, ln(a)⇒1 (because ln(x) is a continuous function in (0,∞) ) and as a consequence f'(x)⇒f(x).

In the graph that is attached it´s shown that the functions follows this inequality (the segmented lines are the derivatives):

if a<e<b, then aˣln(a) < aˣ < eˣ < bˣ < bˣln(b)  (and below we explain why this happen)

Considering that ln(a) is a growing function and ln(e)=1, we have:

if a<e<b, then ln(a)< 1 <ln(b)

if a<e, then aˣln(a)<aˣ

if e<b, then bˣ<bˣln(b)

And because eˣ is defined to be the same as its derivative, the cases above results in the following

if a<e<b, then aˣ < eˣ < bˣ (because this function is also a growing function as "a" and "b" gets closer to e)

if a<e, then aˣln(a)<aˣ<eˣ ( f'(x)<f(x) )

if e<b, then eˣ<bˣ<bˣln(b) ( f(x)<f'(x) )

but as "a"⇒e, the difference between f(x) and f'(x) begin to decrease until it gets zero (when a=e)

3 0
3 years ago
Can someone help me with this math problem please and thank you. :-)
jok3333 [9.3K]

Triangle ABE is isosceles  / Given

AB congruent to AE     / Def isosceles

angle ABE congruent to angle AEB   / Property of isosceles triangles

angle ABD congruent to angle AEC   / Subst different name for same angles

BD congruent to EC     / Given

triange ABD congruent to triange AEC    / Side Angle Side

5 0
2 years ago
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