All categories

2 years ago

On a standard coordinate

Mathematics

2 answers:

bezimeni [28]2 years ago

6 0

I don’t know I’m just doing this for the points I’m sorry ☮️✌️

Mumz [18]2 years ago

6 0

Same doing this for the pointsssssss thanks tho yahayahahyabaj

You might be interested in

Is (p3)4 • p8 = p20 true or false ?

Oduvanchick [21]

P3(4) = p12 them p12 * p8 = P160 (false)

8 0

2 years ago

What is the GCF of 8x^3y^2+20x^2y^4?

DochEvi [55]

Answer:

B) 4x^2y^2

Step-by-step explanation:

8x^3y^2+20x^2y^4

4(2x^3y^2+5x^2y^4)

4x^2(2xy^2+5y^4)

4x^2y^2(2x+5y^2)

So the answer is B

5 0

3 years ago

Express 0.0000000125 in scientific notation

777dan777 [17]

Answer:

1.25 x 10^-8

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Pls help if pls do most important 15 number 20 number 26 number 28 number 30 number 17 number 25 number 22 number 24 number if u

Tamiku [17]

Answer:

Step-by-step explanation:

15. $\frac{cotx+1}{cotx-1} = \frac{cotx+cotx.tanx}{cotx-cotx.tanx} = \frac{cotx(1+tanx)}{cotx(1-tanx)} = \frac{1+tanx}{1-tanx} \\$

16. $\frac{1+cos\alpha }{sin\alpha } = \frac{sin\alpha }{1-cos\alpha }$

$=> (1+cos\alpha )(1-cos\alpha ) = sin^{2} \alpha \\=> 1-cos^{2}\alpha =sin^{2} \alpha \\=> sin^{2}\alpha +cos^{2}\alpha =1\\$

=> The clause is correct

17. Do the same (16)

18. $\frac{sinx}{1-cosx}+\frac{sinx}{1+cosx} = \frac{sinx(1+cosx) + sinx(1-cosx)}{(1+cosx)(1-cosx)} = \frac{sinx + sinx.cosx + sinx - sinx.cosx}{1-cos^{2}x} = \frac{2sinx}{sin^{2}x }= \frac{2}{sinx} = 2cosecx$

19.

$\frac{sinA}{1+cosA} + \frac{1+cosA}{sinA}=\frac{2}{sinA} \\=> \frac{sinA}{1+cosA} + \frac{1+cosA}{sinA} - \frac{2}{sinA} \\ = 0\\=> \frac{sinA}{1+cosA} + (\frac{1+cosA}{sinA} - \frac{2}{sinA} \\) = 0\\=> \frac{sinA}{1+cosA} + \frac{1+cosA-2}{sinA} = 0\\=> \frac{sinA}{1+cosA} +\frac{cosA-1}{sinA} = 0\\=> \frac{sin^{2} A+(cosA-1)(1+cosA)}{(1+cosA)sinA}=0\\=> \frac{sin^{2} A+cos^{2} A-1}{(1+cosA)sinA}=0\\=> \frac{0}{(1+cosA)sinA} =0\\$

=> The clause is correct

20. Do the same (18)

21. Left = $\frac{1}{cosecA+cotA} = \frac{1}{\frac{1}{sinA}+\frac{cosA}{sinA} } = \frac{1}{\frac{1+cosA}{sinA} }= \frac{sinA}{1+cosA}$

Right = $cosecA-cotA = \frac{1}{sinA}-\frac{cosA}{sinA}= \frac{1-cosA}{sinA} \\$

Same with (16) => Left = Right => The clause is correct

22. Do the same (21)

Too long, i'm so lazy :))))

5 0

2 years ago

what is the equation in point-slope form of the line that passes through the point ( -1,,-4) has a slop of a -3

Vesnalui [34]

The answer has to resemble y=Mx+b so to find your y intercept plug in your coordinates into that equation so put your slope in for m and your x intercept in for x and the y intercept in for y so -4= -3(-1)+b now get b alone -1=b so your equation would be y=-3x-1

6 0

3 years ago