2 years ago

On a standard coordinate

Mathematics

2 answers:

bezimeni [28]2 years ago

6 0

I don’t know I’m just doing this for the points I’m sorry ☮️✌️

Mumz [18]2 years ago

6 0

Same doing this for the pointsssssss thanks tho yahayahahyabaj

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Add 84.0393 and 231.6581 and round the sum to the nearest hundredths and thousandths

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rusak2 [61]

Answer:

The distance between the astronomers and the moon was $7.56*10^{8]$ meters.

Step-by-step explanation:

We have that the speed is the distance divided by the time, so:

$v = \frac{d}{t}$

In this problem, we have that:

The reflected laser beam was observed by the astronomers 2.52 s after the laser pulse was sent. This means that $t = 2.52$ .

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$v = \frac{d}{t}$

$d = vt$

$d = 3*10^{8}*2.52$

$7.56*10^{8]$

The distance between the astronomers and the moon was $7.56*10^{8]$ meters.

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3 years ago

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3, 9, 27, 81, 243, 729

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2 years ago

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2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago