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KATRIN_1 [288]
2 years ago
15

Find the unknown side length X.

Mathematics
2 answers:
Basile [38]2 years ago
8 0

Answer: 10

Step-by-step explanation:

Anna007 [38]2 years ago
3 0

Answer:

10

Step-by-step explanation:

square of 8 and 6 then add .you find the square root of the answer

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Answer:

Point A is the center of the circle that passes through points E, F, and G and the center of the circle that passes through points X, Y, and Z.

Step-by-step explanation:

A is the intersection of angle bisectors, so is the incenter of triangle EFG. It is also the intersection of the perpendicular bisectors of the sides of triangle EFG, so is the circumcenter.

The altitudes at X, Y, and Z are perpendicular to sides EF, EG, and FG, and pass through the incenter, so X, Y, Z are points on the incircle.

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3 years ago
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Select all the statements that describe the expression 5 + 2x.
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6 0
3 years ago
Determine whether the given lengths can be sides of a right triangle. Which of the following are true statements. A.The lengths
Stels [109]

Answer:

Given sides 12, 16 and 20 can be the sides of right triangle.

Step-by-step explanation:

Sides of right triangle always follow the Pythagoras theorem.

i.e (base)^2 + (Height)^2 = (Hypotenuse)^2

For the given Lengths 7, 40 and 41

We need to check if

7^2 + 40^2 =41^2 \\or\\ 7^2 + 40^2 \neq41^2

Since \\7^2 + 40^2 = 1649\\and \\41^2 = 1681

That means, \\ 7^2 + 40^2 \neq 41^2

hence 7,40 and 41 can not be the sides of right triangle.

Next,

Given sides 12,16 and 20.

Again follow the similar process used in the above problem.

12^2 + 16^2 =400\\And \\20^2 = 400\\Since 12^2 + 16^2 = 20^2

Therefore given sides 12,16 and 20 can be the sides of right triangle.


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3 years ago
I WILL MARK THE BRAINIEST!!!!!!! WRONG ANSWER'S WILL BE REPORTED!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
trasher [3.6K]
The correct answer should be choice A
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2 years ago
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