[tex]\dfrac{\dfrac{r-5}{9r}}{\dfrac{5-r}{3r^2}}=\dfrac{r-5}{9r}.\dfrac{-3r^2}{r-5}=\dfrac{-r}{3}[\tex]
Answer:
Step-by-step explanation:
The equation for finding the area of a hexagon with a side length is
insert
and you are left with 162\sqrt{3}
Hope that helps :)
Answer:
Step-by-step explanation:
Answer:
it will be 120 -×- will be plus hope ur help and mark me brainlist
-3×-40=120 when we multiply the minus to minus it will be plus