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astraxan [27]
3 years ago
7

Describe how 20,000 and 2,000 related

Mathematics
1 answer:
Ray Of Light [21]3 years ago
5 0

Answer:

They both have 3 zero's both have the number 2

They both are numbers

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Solve the system y = -x + 7 and y = 0.5(x - 3)2
amid [387]

Answer:

(5, 2 ) and (- 1, 8 )

Step-by-step explanation:

Given the equations

y = - x + 7 → (1)

y = 0.5(x - 3)²

   = 0.5(x² - 6x + 9)

y    = 0.5x² - 3x + 4.5 → (2)

Substitute y = - x + 7 into (2)

- x + 7 = 0.5x² - 3x + 4.5 ( subtract - x + 7 from both sides )

0 = 0.5x² - 2x - 2.5 ( multiply through by 2 ) , then

x² - 4x - 5 = 0 ← in standard form

(x - 5)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 5 = 0 ⇒ x = 5

x + 1 = 0 ⇒ x = - 1

Substitute these values into (1) for corresponding values of y

x = 5 : y = - 5 + 7 = 2 ⇒ (5, 2 )

x = - 1 : y = -(- 1) + 7 = 1 + 7 = 8 ⇒ (- 1, 8 )

6 0
3 years ago
Terry is doing his homework he is trying to find the value of x:2 = 30:12 what is the value of x
Luba_88 [7]

jcp-fnoa-kzk join here

8 0
3 years ago
Read 2 more answers
Solve for g<br>-6g + 3g + 12 &gt; -18<br>A.g&lt;2<br>B.g&gt; 2<br>C.g&lt;10<br>D.g&gt; 10​
Minchanka [31]

Answer:

g < 10

Step-by-step explanation:

-6g + 3g + 12 > -18

Combine like terms

-3g +12 > -18

Subtract 12 from each side

-3g+12-12 > -18-12

-3g > -30

Divide each side by -3, remembering to flip the inequality

-3g/-3 < -30/-3

g < 10

4 0
3 years ago
The bucket containing orange tennis balls and yellow tennis balls from which 5 balls are selected at random, but assume that the
NeX [460]

(1)  

Probability that all are yellow = \frac{7\times6\times5\times4\times3}{16\times15\times14\times13\times12}=0.0048

Probability that all are orange = \frac{9\times8\times7\times6\times5}{16\times15\times14\times13\times12}=0.0288

Sum of the two probabilities = 0048+ 0.0288=0.0336

Thus, the probability that at least one is orange and at least one is yellow = 1-0.0336= 0.9664= 96.64 %


(2) In addition to the above, we eliminate the "1 and 4" cases.  

In these cases, any of the 5 can be taken out, so we multiply by 5.  


1 yellow + 4 orange = 5\times \frac{(7 \times 9 \times 8 \times 7 \times 6)}{(16 \times 15 \times 14 \times 13 \times12)}  = 0.2019

1 orange + 4 yellow = 5 \times \frac{(9 \times 7\times 6 \times 5 \times 4)}{(16 \times 15\times 14 \times 13 \times 12)} = 0.0721


Sum of two probabilities = 0.2019+0.0721=0.2740  

Now adding 0.0336 to this probability =0.0336+0.2740= 0.3076  


Subtracting that from 1.0000 = 1-0.3076=0.6924= 69.24 %

Thus, the probability that, of the 5 balls selected at random, at least two are orange and at least two are yellow= 69.24%


4 0
3 years ago
Help. I’m failing math and I need to finish 15 khans by tomorrow
erma4kov [3.2K]

Answer:

80

Step-by-step explanation:

8 0
3 years ago
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