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3 years ago

Can someone plz help ASAP -5+30<-10

Mathematics

2 answers:

Ne4ueva [31]3 years ago

7 0

Answer:

Its False

Step-by-step explanation:

25<-10

False

Zigmanuir [339]3 years ago

6 0

Answer:

This is False

Step-by-step explanation:

-5+30<-10

False

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What time is it 7 in a half hours before 2:12 am

scoray [572]

6.42 pm is the answer. You can think backward 8 hours before 2:12 am, which is 6:12pm. Now, go 'forward' a half an hour, to 6:42pm. Answer: 6:42pm.

5 0

3 years ago

Wendy’s offers eight different condiments (mustard, catsup, onion, mayonnaise, pickle, lettuce, tomato, and relish) on hamburger

julsineya [31]

Answer:

Check the explanation

Step-by-step explanation:

Conclusion: young people like condiments.

First, let's convert things into percentages, since the number in each age category is different. There are 143 in "Under 18", 233 in "18 to 40", 161 in "40 to 60", and 122 in "over 60".

Of the under 18s: 71 of 143 = 49.7% order three or more.

Of the 18-40s: 87 of 233 = 37.3% order three or more.

Of the 40-60s: 47 of 161 = 29.2% order three or more.

Of the 60 and ups: 28 of 122 = 23.0% order three or more.

The older you are, the less likely you are to order lots of condiments.

4 0

3 years ago

An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y

aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average time = 23.92 minutes

s = sample standard deviation = 6.72 minutes

n = sample of times = 40

$\mu$ = population mean assembly time

Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, a 98% confidence interval for the population mean, $\mu$ is;

P(-2.426 < $t_3_9$ < 2.426) = 0.98 {As the critical value of z at 1% level