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Vika [28.1K]
3 years ago
10

How do U Graph the line y=4x?

Mathematics
1 answer:
Luba_88 [7]3 years ago
5 0

Answer:

Graph the line using slope and y-intercept, or two points. Slope: 4 Y-intercept: 0,0

Step-by-step explanation:

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David says he has 2/3 of a pipe length​ left, while Don says he has 11/16 of a length left. Which person has the longest section
Kruka [31]

Answer:

Don

Step-by-step explanation:

1. We make the fractions have common denominators so it is easier to compare them. We can do this buy multiplying 2/3 by a factor of 16, so it becomes 32/48. For 11/16, we multiply by a factor of 3 so it becomes 33/48. It is now apparent that Don has the longer pipe.

5 0
4 years ago
Find the length of LM. Show your work.
kicyunya [14]

Answer:

<h2>20</h2>

<em>Solution</em><em>,</em>

<em><</em><em>N=</em><em>1</em><em>8</em><em>0</em><em>-</em><em>5</em><em>3</em><em>-</em><em>4</em><em>4</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>8</em><em>3</em>

<h3><em>Apply </em><em>sines </em><em>rule,</em></h3>

<em>\frac{lm}{sin \: 83}  =  \frac{14}{sin44}  \\ lm =  \frac{14 \: sin \: 83}{sin \: 44}  \\ lm = 20</em>

<em>hope </em><em>this </em><em>helps.</em><em>.</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em>

4 0
3 years ago
Read 2 more answers
Jamie has 105 pieces of candy leftover from Halloween. She would like to distribute them evenly to the 7 kids on her block. Writ
-Dominant- [34]

Answer:

x=105÷7

Step-by-step explanation:

You have to split the candy with 7 people and you can't split people

7 0
3 years ago
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What is the y-intercept of the line -7x-5y=-45?
Goshia [24]

Answer:

The y-intercept is at the point (0, 9).

Step-by-step explanation:

WE have the y intercept when x = 0:

-7(0) - 5y = -45

-5y = -45

y = -45/-5 = 9.

7 0
3 years ago
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Which expression is equivalent to 4^ 5x4^ -7÷4 ^-2?
Andre45 [30]

\bf ~~~~~~~~~~~~\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} \qquad \qquad \cfrac{1}{a^n}\implies a^{-n} \qquad \qquad  a^n\implies \cfrac{1}{a^{-n}}\\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 4^5\cdot 4^{-7}\div 4^{-2}\implies \cfrac{4^5\cdot 4^{-7}}{4^{-2}}\implies \cfrac{4^{5-7}}{4^{-2}}\implies \cfrac{4^{-2}}{4^{-2}}\implies 4^{-2}\cdot 4^2 \\\\\\ 4^{-2+2}\implies \boxed{4^0}\implies 1

5 0
3 years ago
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