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Brut [27]
3 years ago
11

Evaluate the expression 12 - x when x = 4. Show your work.

Mathematics
2 answers:
Artemon [7]3 years ago
8 0
12-4 is the answer see
ArbitrLikvidat [17]3 years ago
6 0

Answer: 8

Step-by-step explanation: 12 minus 4 equals 8

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80 hours of labor work 40 assistant 25 hr earn $22per hour 15 per hr. earn$10 how much labor
Vlada [557]
80 hr total
the assistants is not info
25 hr X $22 per = $500
15 hr X $10 = $150
$500 + $150 = $650
now for hr you have 80, you worked 25 + 15 = 40, 80 - 40 = 40
your answer is 40 --------------------------------------|^|
your welcome

6 0
4 years ago
Write the number from least to greatest 0.6 1/2 2/3 0.39
Masja [62]

Answer:

0.39,\frac{1}{2},0.6,\frac{2}{3}

Step-by-step explanation:

Since \frac{1}{2}=0.5, this would go behind 0.6, and since \frac{2}{3}=0.6\bar{6}, this would go in front of 0.6

Hence, the order of the numbers from least to greatest would be 0.39,\frac{1}{2},0.6,\frac{2}{3}

8 0
2 years ago
ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions
4vir4ik [10]

Answer:

the 3rd one

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
Owen is planning surgery to repair the torn ligament in his knee. The total cost of the surgery is expected to be about $7,000.
igor_vitrenko [27]

Answer:

$2200

Step-by-step explanation:

Given that Owen has $7000 to pay, with a $1000 deductible. This means that he has, left to pay, $6000.

Again, we're told that he has 20% Co pay for the procedure. Taking 20% of $6000, we have

20/100 * 6000 = $1200. This means be has $1200 to co pay for the procedure.

Adding this newly calculated $1200 with the previously set aside $1000, we have a total of $2200. This is the price Owen will pay from his part, as part of the surgery

5 0
3 years ago
Two bicyclists leave the center of town at the same time. One heads due north and the other heads due west. Later, the two cycli
Ad libitum [116K]
This  situation is represented  in annex. 
From Pythagorean theorem you've got equation:
x^2+(x+5)^2=25 \\ \\ \hbox{From formula} \ \ \ (a+b)^2 = a^2+2ab+b^2: \\ \\ x^2+x^2+10x+25=25 \\ 2x^2+10x=0 \\ \\ \hbox{Factor out} \ \ 2x: \\ 2x(x+5)=0 \\ \\ \hbox{So you've got:} \\ \\ x_1=0 \\ x_2=-5

There isn't any solutions where x>0, so this situation is IMPOSSIBLE.

Did you write correctly this question....?

3 0
3 years ago
Read 2 more answers
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