Ask question

Ask question

All categories

3 years ago

7

Pls help I would really appreciate it

2 answers:

Nadusha1986 [10]3 years ago

8 0

Answer:

the ANWER IS B

Step-by-step explanation:

It B BECAUSE I AM SMART

Rina8888 [55]3 years ago

6 0

The answer would be the first one , A .

You might be interested in

10 chocolates for $2.30 how much is it for 1 strawberry?

Ivan

Answer:

23 cents (.23)

Step-by-step explanation:

2.30 divided by 10

4 0

3 years ago

One letter tile is redrawn form the bag abd replaced 300 times. Predict how many times a consonant will not be picked.

algol13

239 times i think, hope this helped

6 0

3 years ago

What're all the numbers divisible by 3 and 9?

KIM [24]

3 and 1 are divisible by 3. 3, 1, and 9 are divisible by 9

7 0

3 years ago

Read 2 more answers

Expand.<br> Your answer should be a polynomial in standard form.<br> (x-3)(x-4)=

nekit [7.7K]

Answer:

Step-by-step explanation:

So, it's x*x+x*-3+-4*x+3*-3

That simplifies to x^2 - 7x + 12

5 0

3 years ago

Find the equation of the tangent line to the curve (a lemniscate)

olya-2409 [2.1K]

Answer:

$m=\frac{9}{13}$ and $b=\frac{40}{13}$

Step-by-step explanation:

The equation of curve is

$2(x^2+y^2)^2=25(x^2-y^2)$

We need to find the equation of the tangent line to the curve at the point (-3, 1).

Differentiate with respect to x.

$2[2(x^2+y^2)\frac{d}{dx}(x^2+y^2)]=25(2x-2y\frac{dy}{dx})$

$4(x^2+y^2)(2x+2y\frac{dy}{dx})=25(2x-2y\frac{dy}{dx})$

The point of tangency is (-3,1). It means the slope of tangent is $\frac{dy}{dx}_{(-3,1)}$ .

Substitute x=-3 and y=1 in the above equation.

$4((-3)^2+(1)^2)(2(-3)+2(1)\frac{dy}{dx})=25(2(-3)-2(1)\frac{dy}{dx})$

$40(-6+2\frac{dy}{dx})=25(-6-2\frac{dy}{dx})$

$-240+80\frac{dy}{dx})=-150-50\frac{dy}{dx}$

$80\frac{dy}{dx}+50\frac{dy}{dx}=-150+240$

$130\frac{dy}{dx}=90$

Divide both sides by 130.

$\frac{dy}{dx}=\frac{9}{13}$

If a line passes through a points $(x_1,y_1)$ with slope m, then the point slope form of the line is

$y-y_1=m(x-x_1)$

The slope of tangent line is $\frac{9}{13}$ and it passes through the point (-3,1). So, the equation of tangent is

$y-1=\frac{9}{13}(x-(-3))$

$y-1=\frac{9}{13}(x)+\frac{27}{13}$

Add 1 on both sides.

$y=\frac{9}{13}(x)+\frac{27}{13}+1$

$y=\frac{9}{13}(x)+\frac{40}{13}$

Therefore, $m=\frac{9}{13}$ and $b=\frac{40}{13}$ .

5 0

3 years ago