they have adapted by regulating their body temperature in different ways.
The answer is C. We can suppose that the Grey gene is "A" and Black gene is "a". So the gene of heterozygous grey fruit fly is "Aa", and the black-bodied fruit fly is "aa". After mating, the offspring can get only "a" from balck-bodied fruit fly and has equal opportunity to get a "A" or "a" from heterozygous grey fruit fly. If the gene of offspring is "Aa", it will be grey. If "aa", it will be black. So the proportion of being black is 0.5.
Answer:
He said they all came from one ancestral species.
Explanation:
They all came from the same species but mutations due to their differing habitats changed them all slightly.
The mix of alleles from various genes that end up in the daughter cells is determined by the anaphase 1 of meiosis 1.
Chromosome segregation during meiosis is mirrored in the segregation of alleles. During anaphase, 1 of meiosis 1 homologous chromosomal separation leads to allele segregation.
Chromosomes display autonomous assortment when they are randomly split into daughter cells during meiosis.
<h3>What takes place in anaphase 1?</h3>
During meiosis I, sister chromatids remain together as homologous chromosomes separate. To appreciate the development of germ cells, it is crucial to comprehend how this odd chromosomal segregation behavior came to be. Here, we show that the pattern of chromosomal segregation during meiosis I is determined by the microtubule-kinetochore interactions that are inhibited during prophase I and the premeiotic S phase.
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Carbon dioxide and water
<span>C6</span><span>H12</span><span>O6</span>+<span>O2</span>→<span>CO2</span>+<span>H2</span>O+<span>energy</span>
