Ba + 3ca = -2 Solve for a

Mathematics

1 answer:

monitta3 years ago

3 0

We have:

ba + 3ca = -2

Extract common factor "a":

a(b + 3c) = -2

Divide by the term (b + 3c):

$a = \dfrac{-2}{b+3c}$

You might be interested in

Which expression is equivalent to the given expression?

mel-nik [20]

The answer would be b.

3 0

3 years ago

Read 2 more answers

Given parallelogram ABCD, solve for X

shtirl [24]

Opposite sides of a parallelogram are congruent, so make BC and AD equal to each other in an equation.

BC = AD

16 + 2x = 10 + 8x

Subract 2x from both sides.

16 = 10 + 6x

Subtract 10 from both sides.

6 = 6x

Divide both sides by 6.

x = 1

B) 1 is your answer.

3 0

3 years ago

How do you find the surface area of a triangle prism

valentinak56 [21]

Answer: I got it

Step-by-step explanation:

SA = bh + (s1 + s2 + s3)H

6 0

3 years ago

In a normal distribution, what percent of the values lie above the mean?

Leya [2.2K]

In statistics, the 68–95–99.7 rule, also known as the empirical rule, is a shorthand used to remember the percentage of values that lie within a band around the mean in a normal distribution with a width of two, four and six standard deviations, respectively; more accurately, 68.27%, 95.45% and 99.73% of the values lie .

5 0

4 years ago

Assume that there are 22 frozen dinners: 12 pasta, 6 chicken, and 4 seafood dinners. The student selects 5 of them. What is the

Stells [14]

Since, there are 22 frozen dinners. Out of these, 22 are pasta, 6 chicken and 4 seafood dinners.

We have to determine the probability that at least 2 of the dinners selected are pasta dinner. At least 2 of the dinners selected are pasta, it means that there can be 2 pasta, 3 , 4 or 5.

So, Probability with at least 2 of dinners

= $\frac{(^{12}C_{2} \times ^{10}C_{3})+ (^{12}C_{3} \times ^{10}C_{2})+(^{12}C_{4} \times ^{10}C_{1})+(^{12}C_{5})}{^{22}C_{5}}$