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3 years ago

14

Jace and Ellie are helping their friend Oliver move: Jace can move one box for every two boxes does Elle can move five boxes how

many boxes can move

1 answer:

Simora [160]3 years ago

3 0

Answer:

Two.

Step-by-step explanation:

If Ellie moves five boxes, and Jace can move one for every two Ellie moves, Jace can move two boxes.

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A computer store bought a coat of $10 and sold if for $13 find the percent increase

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Step-by-step explanation:

30 is 30 percent of 100 so the answer is 30 percent increase

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3 years ago

The best fit line is given by the equation y = 0.404x - 5.18, where y represents the height of the plant above ground level, and

IRISSAK [1]

Step-by-step explanation:

<u>The line of best fit given:</u>

y = 0.404x - 5.18

<u>It is given in the slope-intercept form:</u>

y = mx + b, where m- slope, b - y-intercept

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It seems reasonable but without means of control it is difficult to trace the growth while still under the ground, during the first 13-14 days.

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2 years ago

Mallory works 20 hours a week as a website designer and earns $42.50 per hour. If Mallory saves

AleksandrR [38]

If Mallory makes $42.50 per hour and she works 20 hours a week, we multiple those two and we get:

42.5 * 20 = 850

So she earns $850 per week.

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In 4 weeks she would have:

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3 years ago

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Someone please be awesome and help me please :(

solong [7]

Answer:

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Step-by-step explanation:

$x^2+\frac{b}{a}x+\frac{c}{a}=0$

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared. Whatever you add in, you must take out.

$x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

Now we are read to write that one part (the first three terms together) as a square:

$(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

I don't see this but what happens if we find a common denominator for those 2 terms after the square. (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

$(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0$

They put it in ( )

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

I'm going to go ahead and combine those fractions now:

$(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0$

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

$(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0$

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

$x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}$

$x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}$

Now subtract b/(2a) on both sides:

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Combine the fractions (they have the same denominator):

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

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3 years ago