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2 years ago

This figure consists of a rectangle and semicircle.

Mathematics

2 answers:

zalisa [80]2 years ago

4 0

Answer:

46.28

Step-by-step explanation:

Zepler [3.9K]2 years ago

3 0

Answer:

Step-by-step explanation:

Radius of semicircle = 2 ft

Area of semicircle = 0.5πr² = 0.5π2² = 6.28 sq ft

Area of rectangle = 10 × 4 = 40 sq ft

Total area = 46.28 sq ft

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2 years ago

F(t)=t^2+19t+60<br> What are the zeros of the function and what is the vertex of the parabola?

SVEN [57.7K]

Answer: $-4,-15;\ \left(-\dfrac{19}{2},-\dfrac{121}{4}\right)$

Step-by-step explanation:

Given

Function is $F(t)=t^2+19+60$

Zeroes of the function are

$t^2+19t+60=0\\\\\Rightarrow t=\dfrac{-19\pm\sqrt{19^2-4\times 1\times 60}}{2\times 1}\\\\\Rightarrow t=\dfrac{-19\pm \sqrt{121}}{2}\\\\\Rightarrow t=\dfrac{-19\pm 11}{2}\\\\\Rightarrow t=-4,-15$

Using completing the square method

$y=t^2+2\times \dfrac{19}{2}t+\dfrac{19^2}{2^2}-\dfrac{19^2}{2^2}+60\\\\y=\left(t+\dfrac{19}{2}\right)^2+60-\dfrac{361}{4}\\\\y=\left(t+\dfrac{19}{2}\right)^2-\dfrac{121}{4}\\\\y+\dfrac{121}{4}=\left(t+\dfrac{19}{2}\right)^2\\\\\left(y-(-\dfrac{121}{4}\right)=\left(t-(-\dfrac{19}{2})\right)^2\\\\\text{The vertex is }\left(-\dfrac{19}{2},-\dfrac{121}{4}\right)$

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2 years ago

One year, the population of a city was 225,000. Several years later it was 236,250. Find the percent increase.

vampirchik [111]

Based on the information given the percentage increase is 5%.

<h3>Percentage increase</h3>

Using this formula

Percentage increase=Population several years later-Population for year/Population for one year×100%

Let plug in the formula

Percentage increase=236,360-225,000/225,000×100

Percentage increase=5%

Inconclusion the percentage increase is 5%.

Learn more about percentage increase here:brainly.com/question/11360390

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2 years ago