Answer:
Matias divided 7.6 by 10 raised to the power of -2.
Step-by-step explanation:
Given : Matias preformed an operation with 7.6 and a number. He ended up moving the decimal point in 7.6 two places to the left.
To find : Matias divided 7.6 by 10 raised to the power of ?
Solution :
Matias preformed an operation with 7.6 and a number.
He ended up moving the decimal point in 7.6 two places to the left we have to multiply it with 0.01
i.e. 
So, Matias divided 7.6 by 10 raised to the power of -2.
Answer:

Step-by-step explanation:
Given function:

where:
- h = height (in feet)
- t = times (in seconds)
Rewrite in the form 
The quickest way to do this is to expand
and compare coefficients with the original function.

Comparing coefficients with 



Therefore, substituting the found values into the equation:

Answer:graph a
Step-by-step explanation:
bc if you subtract 3
from 2 you find the one you line your numbers up with
Answer:
Probably shouldn't cheat on tests
Step-by-step explanation:
just sayinnn
:/
Pretty sure option 4 is your answer though. Not 100% because the picture is a bit blurry
g(x)=x^2-1
f(g(X))=5 sqrt(x^2-1+1)-2
5 sqrt(x^2)-2
:sqrt cancel the square
5x-2