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Softa [21]
3 years ago
9

The following dataset represents the math test scores for a class of 20 students. 90, 85, 95, 100, 100, 90, 100, 65, 100, 85, 80

, 95, 80, 100, 85, 75, 100, 90, 90, 75 Would the mode be a good measure of central tendency for this dataset?
Mathematics
1 answer:
neonofarm [45]3 years ago
3 0

Answer:

yes

Step-by-step explanation:

The mode is the measure of the central tendency for the given data set. The mode represents the highest frequency of the number

Since in the given data set as we can see that the 100 would be appeared 6 times

So this represent that the mode is 100

So here the mode would be the good measure

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A line is perpendicular to y=2/3x +2/3 and intersects the point (-2,4). what is the equation of this perpendicular line?
TiliK225 [7]

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5 0
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Calculate: 3400*6 1/2 *1/100​
marishachu [46]

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7 0
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While in transit, the antitoxin had to stay between 36ºF and 46ºF. The dogsled teams stopped along the route often to warm the a
eimsori [14]
Range is the difference between the largest and the smallest numbers in a given contest

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6 0
2 years ago
According to the US Bureau of labor statistics, 7% of US female workers between 16 and 24 years old are paid at the minimum wage
vladimir1956 [14]

Answer:

The Null Hypothesis is  H_o:k_o = 0.07

The alternative hypothesis is  H_a :k_o \ne 0.07

Decision rule

    If the test staistics is  greater than the critical value of significance level then H_o is accepted else H_o  is rejected

With the above in mind

       The critical value of the significance level which is obtained from the table is

     t_{0.05} = 1.645

Now since the critical value of significance level is greater than the test  staistics then the null hypothesis will be rejected

Conclusion

The information is not enough to back the claim that state differs from the nation

Step-by-step explanation:

From the question we are told that

The percentage of US female workers paid at the minimum wage or less is  k_o = 7% = 0.07

  The sample size is  n =  500

    The number paid minimum wage or less is  x = 42

    The significance level is \alpha  =5%  = 0.05

Now the probability of getting a US female workers paid at the minimum wage or less is mathematically represented as

         \= k = \frac{x}{n}

substituting value

        \= k = \frac{42}{500}

        \= k = 0.084

The Null Hypothesis is  H_o:k_o = 0.07

The alternative hypothesis is  H_a :k_o \ne 0.07

Generally the test statistics is mathematically evaluated as

        z =  \frac{\=  k  - k_o}{\sqrt{\frac{k_o(1-k_o)}{n} } }

substituting value

      z =  \frac{0.084  - 0.07}{\sqrt{\frac{0.07 (1-0.07)}{500} } }

     z =  1.23

Now the Decision rule is stated as  

        If the test staistics is  greater than the critical value of significance level then H_o is accepted else H_o  is rejected

With the above in mind

       The critical value of the significance level which is obtained from the table is

     t_{0.05} = 1.645

Now since the critical value of significance level is greater than the test  staistics then the null hypothesis will be rejected

   So the conclusion will be

   The information is not enough to back the claim that state differs from the nation

 

4 0
3 years ago
4(5+ab) where a=-3.5 and b-0.8
lozanna [386]

Answer:

31.2

Step-by-step explanation:

4(5 + (- 3.5 × - 0.8)

4(5 + 2.8)

4(7.8)

31.2

6 0
3 years ago
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