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leonid [27]
3 years ago
6

Cell phone bills are based on a flat

Mathematics
1 answer:
hodyreva [135]3 years ago
6 0

Answer:

a

Step-by-step explanation:

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(a) Work out the reciprocal of 1.25
Oxana [17]

Answer:

0.8 OR \frac{4}{5}

Step-by-step explanation:

The reciprocal of any number is the number that it multiplies by to equal 1.

The reciprocal can be found by simply converting the number into a fraction and then 'flipping' the fraction as any number multiplied by its reciprocal is 1.

E.g.

No. X/Y * Y/X (its reciprocal) = 1

\frac{x}{y} *\frac{y}{x} =\frac{xy}{xy} =1

So, to find the reciprocal of 1.25,we should first convert 1.25 to a fraction.

1.25 = 125/100

\frac{125/25}{100/25}=\frac{5}{4}

Now we just flip 5/4 to get our reciprocal:

\frac{4}{5} = 0.8

Test: 0.8 * 1.25 = 1

The reciprocal of 1.25 (\frac{5}{4}) is 0.8 (\frac{4}{5}).

Hope this helped!

8 0
3 years ago
A triangular lamina has vertices (0, 0), (0, 1) and (c, 0) for some positive constant c. Assuming constant mass density, show th
a_sh-v [17]

The equation of the line through (0, 1) and (<em>c</em>, 0) is

<em>y</em> - 0 = (0 - 1)/(<em>c</em> - 0) (<em>x</em> - <em>c</em>)   ==>   <em>y</em> = 1 - <em>x</em>/<em>c</em>

Let <em>L</em> denote the given lamina,

<em>L</em> = {(<em>x</em>, <em>y</em>) : 0 ≤ <em>x</em> ≤ <em>c</em> and 0 ≤ <em>y</em> ≤ 1 - <em>x</em>/<em>c</em>}

Then the center of mass of <em>L</em> is the point (\bar x,\bar y) with coordinates given by

\bar x = \dfrac{M_x}m \text{ and } \bar y = \dfrac{M_y}m

where M_x is the first moment of <em>L</em> about the <em>x</em>-axis, M_y is the first moment about the <em>y</em>-axis, and <em>m</em> is the mass of <em>L</em>. We only care about the <em>y</em>-coordinate, of course.

Let <em>ρ</em> be the mass density of <em>L</em>. Then <em>L</em> has a mass of

\displaystyle m = \iint_L \rho \,\mathrm dA = \rho\int_0^c\int_0^{1-\frac xc}\mathrm dy\,\mathrm dx = \frac{\rho c}2

Now we compute the first moment about the <em>y</em>-axis:

\displaystyle M_y = \iint_L x\rho\,\mathrm dA = \rho \int_0^c\int_0^{1-\frac xc}x\,\mathrm dy\,\mathrm dx = \frac{\rho c^2}6

Then

\bar y = \dfrac{M_y}m = \dfrac{\dfrac{\rho c^2}6}{\dfrac{\rho c}2} = \dfrac c3

but this clearly isn't independent of <em>c</em> ...

Maybe the <em>x</em>-coordinate was intended? Because we would have had

\displaystyle M_x = \iint_L y\rho\,\mathrm dA = \rho \int_0^c\int_0^{1-\frac xc}y\,\mathrm dy\,\mathrm dx = \frac{\rho c}6

and we get

\bar x = \dfrac{M_x}m = \dfrac{\dfrac{\rho c}6}{\dfrac{\rho c}2} = \dfrac13

8 0
3 years ago
A garden supply store sells two types of lawn mowers.Total sales of mowers for the year were $8379.79. The total number of mower
kherson [118]
Value + value = 8379.70
249.99x + 329.99*30-329.99x = 8379.70
-80x + 9899.70 = 8379.70
-80x = -1520.00
x = 19 (number of the cheaper mowers sold)
30-x = 11 (number of more expensive mowers sold)
3 0
4 years ago
Read 2 more answers
What is the end behavior of g(x) = (x + 7)(x + 1)(x − 1)

?<br> Will give Brainiest
nadezda [96]

Answer:

Step-by-step explanation:

the end behavior refers to what happens when x approaches negative infinity and infinity

as x approaches negative infinity (to the left), the values are all negative inside the parentheses so multiplying -∞ * -∞ * -∞, you get g(x) approaches -∞ as x approaches -∞

as x approaches ∞(to the right), the values inside the parentheses are all positive ∞ so multiplying ∞*∞*∞, you get g(x) approaches ∞ as x approaches ∞

8 0
3 years ago
The scale factor of the blueprint of a front door to the actual front door is 0.04. The area of the actual front door is 36ft2.
Serjik [45]
1.44ft2. I worked it out on paper and that is what came out of the problem
7 0
4 years ago
Read 2 more answers
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