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2 years ago

Given that

Mathematics

1 answer:

MissTica2 years ago

4 0

Answer:

-2

Step-by-step explanation:

Hey there!!

if we evaluate the expression it will look like :

3x + 14 = 8

and if we solve it:

3x+14=8

Step 1: Subtract 14 from both sides.

3x+14−14=8−14

3x=−6

Step 2: Divide both sides by 3.

3x/3 = -6/3

x= −2

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Find gradient xe^y + 4 ln y = x² at (1, 1)

cricket20 [7]

$xe^y+4\ln y=x^2$

Differentiate both sides with respect to x, assuming y = y(x).

$\dfrac{\mathrm d(xe^y+4\ln y)}{\mathrm dx}=\dfrac{\mathrm d(x^2)}{\mathrm dx}$

$\dfrac{\mathrm d(xe^y)}{\mathrm dx}+\dfrac{\mathrm d(4\ln y)}{\mathrm dx}=2x$

$\dfrac{\mathrm d(x)}{\mathrm dx}e^y+x\dfrac{\mathrm d(e^y)}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x$

$e^y+xe^y\dfrac{\mathrm dy}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x$

Solve for dy/dx :

$e^y+\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x$

$\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x-e^y$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x-e^y}{xe^y+\frac4y}$

If y ≠ 0, we can write

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2xy-ye^y}{xye^y+4}$

At the point (1, 1), the derivative is

$\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=1,y=1}=\boxed{\dfrac{2-e}{e+4}}$

4 0

3 years ago

PLS PLS PLS I NEED HELP Given * inserted picture* find

Gala2k [10]

Answer:

SinA=5/1 3 CosA=12/13 tanA=5/12. SinC=12/13 CosC=5/13 and tanC=12/5

Step-by-step explanation:

Basically find the third side by Pythagorean theorem which would get you 13. So 13 is the hypotenuse. Remember these 3 formulas. Sin=Opposite/Hypotenuse Cos=Adjacent/hypotenuse and Tan=opposite/Adjacent. So for Sin a the opposite side to angle A is 5. The hypotenuse is always the same which would be 13. So Sin a is 5/13. For cos the side adjacent would be 12. So it is 12/13. *Note Hypotenuse cannot be considered the adjacent.

4 0

3 years ago

Read 2 more answers

What is the arc measure of BDC in degrees? (4k + 159) P (2k + 153)

andre [41]

<h2>Explanation:</h2><h2></h2>

The diagram is missing but I'll assume that the arc BDC is:

$(4k + 159)^{\circ}$

And another arc, let's call it FGH. measures:

$(2k + 153)^{\circ}$

If those arc are equal, then this equation is true:

$(4k + 159)^{\circ}=(2k + 153)^{\circ} \\ \\ (4k + 159)=(2k + 153) \\ \\ \\ Solving \ for \ k: \\ \\ 4k-2k=153-159 \\ \\ 2k=-6 \\ \\ k=-\frac{6}{2} \\ \\ k=-3$

Substituting k into the first equation:

$\angle BDC=(4(-3)+159)^{\circ} \\ \\ \angle BDC=(-12+159)^{\circ} \\ \\ \boxed{\angle BDC=147^{\circ}}$

3 0

2 years ago

Read 2 more answers

Please help and explain very easy good luck

Mars2501 [29]

Answer:

-76

Step-by-step explanation:

A positive digit multiplied by a negative digit will result as a negative digit.

So,

6 · -8 = -48

Now if there is a problem where a number is added by a negative digit number, you turn the "plus" sign into a "negative" sign.

So,

- 48 + (- 28)

-48 - 28

If you subtract a negative by a negative, the answer will be negative BUT you have to ADD those two negative digits together and put the negative sign after.

- 48 - 28 = -76

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2 years ago

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Two dice are tossed what is the probability of obtaining a sum greater than 6

katrin2010 [14]

7/12 because it would come out to be 21/36, and the simplified version of that is 7/12

5 0

2 years ago