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arsen [322]
3 years ago
5

It cost Evan $17.70 to send 177 text messages how many text messages did he send if he spent $19.10

Mathematics
1 answer:
tatuchka [14]3 years ago
3 0
He sent 191 text messages
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Find the circumference of a circle with radius, r = 3.5m.<br>Give your answer in terms of pi​
anyanavicka [17]

Answer:

Find the circumference of a circle with radius, r = 3.5m.

2x3.5xpi = 7pi is answer

4 0
3 years ago
Layla bought a pencil for $1.25, a pen for $2.25, and three erasers for $0.45 each. She gave the cashier $10 for the items. How
snow_lady [41]

Answer:

1.25+2.25+(o.45 x 3)

=6.95

10-6.95

= got back $3.05

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Use the X method to find the solutions of<br> 62 + 2x - 20 = 0.
inysia [295]

Answer:

x = -21

Step-by-step explanation:

62 + 2x - 20 = 0.

Combine like terms

42 +2x =0

Subtract 42 from each side

42-42 +2x = 0-42

2x = -42

Divide each side by 2

2x/2 = -42/2

x = -21

3 0
3 years ago
Read 2 more answers
The thicknesses of 81 randomly selected aluminum sheets were found to have a variance of 3.23. Construct the 98% confidence inte
Yuliya22 [10]

Answer:

The confidence interval for the population variance of the thicknesses of all aluminum sheets in this factory is Lower limit = 2.30, Upper limit = 4.83.

Step-by-step explanation:

The confidence interval for population variance is given as below:

[(n - 1)\times S^{2}  /  X^{2}  \alpha/2, n-1 ] < \alpha < [(n- 1)\times S^{2}  / X^{2} 1- \alpha/2, n- 1 ]

We are given

Confidence level = 98%

Sample size = n = 81

Degrees of freedom = n – 1 = 80

Sample Variance = S^2 = 3.23

X^{2}_{[\alpha/2, n - 1]}   = 112.3288\\\X^{2} _{1 -\alpha/2,n- 1} = 53.5401

(By using chi-square table)

[(n – 1)*S^2 / X^2 α/2, n– 1 ] < σ^2 < [(n – 1)*S^2 / X^2 1 -α/2, n– 1 ]

[(81 – 1)* 3.23 / 112.3288] < σ^2 < [(81 – 1)* 3.23/ 53.5401]

2.3004 < σ^2 < 4.8263

Lower limit = 2.30

Upper limit = 4.83.

8 0
2 years ago
How many different four-person relay teams can be chosen from eight students
aliina [53]
Slot method

8 optionns n 1st slot
7 options in 2nd slot (since 1 is at 1st slot)
6 options in 3rd slot
5 options in 4th slot

8*7*6*5=1680 ways
6 0
3 years ago
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