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icang [17]
3 years ago
12

When parallel lines are cut by a transversal and you have one acute angle and one obtuse angle, those two angles will always add

up to
Mathematics
2 answers:
alexandr1967 [171]3 years ago
8 0

Answer:

180 maybe ...........

PtichkaEL [24]3 years ago
5 0
180 degrees
A straight line is 180 so that’s why
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My family and I are so confused on this! Help please!
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Answer:

10) Correct

11) Each row is equal to 12 when you multiply them together.

12) 24

Step-by-step explanation:

12) You multiply 4*3*2 to get the volume of 24, which is also the number of cubes needed to make the shape.

<u>Please</u><u> give</u><u> brainliest</u><u> if</u><u> I</u><u> helped</u><u>!</u><u> </u><u>:</u><u>)</u>

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2 years ago
Choose the simplified form of the fifth term of the expansion. -60x2y8 -30x2y8 30x2y8 60x2y8
Vika [28.1K]

Answer:

Answer is D on edge

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
COMPUTE<br><br> 3 ( 2 1/2 - 1 ) + 3/10
Juli2301 [7.4K]

Answer:

<h3>\boxed{ \frac{24}{5} }</h3>

Step-by-step explanation:

\mathsf{3(2 \frac{1}{2}  - 1) +  \frac{3}{10} }

Convert mixed number to improper fraction

\mathrm{3( \frac{5}{2}  - 1) +  \frac{3}{10} }

Calculate the difference

⇒\mathrm{3( \frac{5 \times 1}{2 \times 1} -  \frac{1 \times 2}{1 \times 2}  }) +  \frac{3}{10}

⇒\mathrm{ 3 \times( \frac{5}{2}  -  \frac{2}{2}) } +  \frac{3}{10}

⇒\mathrm{3 \times ( \frac{5 - 2}{2} ) +  \frac{3}{10} }

⇒\mathrm{3 \times  \frac{3}{2}  +  \frac{3}{10} }

Calculate the product

⇒\mathrm{ \frac{3 \times 3}{1 \times 2}  +  \frac{3}{10} }

⇒\mathrm{ \frac{9}{2}  +  \frac{3}{10}}

Add the fractions

⇒\mathsf{ \frac{9  \times 5}{2 \times 5}  +  \frac{3 \times 1}{10 \times 1} }

⇒\mathrm{ \frac{45}{10}  +  \frac{3}{10} }

⇒\mathrm{ \frac{45 + 3}{10 } }

⇒\mathrm{ \frac{48}{10} }

Reduce the numerator and denominator by 2

⇒\mathrm{ \frac{24}{5} }

Further more explanation:

<u>Addition </u><u>and </u><u>Subtraction</u><u> </u><u>of </u><u>like </u><u>fractions</u>

While performing the addition and subtraction of like fractions, you just have to add or subtract the numerator respectively in which the denominator is retained same.

For example :

Add : \mathsf{ \frac{1}{5}  +  \frac{3}{5}  =  \frac{1 + 3}{5} } =  \frac{4}{5}

Subtract : \mathsf{ \frac{5}{7}  -  \frac{4}{7}  =  \frac{5 - 4}{7}  =  \frac{3}{7} }

So, sum of like fractions : \mathsf{ =  \frac{sum \: of \: their \: number}{common \: denominator} }

Difference of like fractions : \mathsf{ \frac{difference \: of \: their \: numerator}{common \: denominator} }

<u>Addition </u><u>and </u><u>subtraction</u><u> </u><u>of </u><u>unlike </u><u>fractions</u>

While performing the addition and subtraction of unlike fractions, you have to express the given fractions into equivalent fractions of common denominator and add or subtract as we do with like fractions. Thus, obtained fractions should be reduced into lowest terms if there are any common on numerator and denominator.

For example:

\mathsf{add \:  \frac{1}{2}  \: and \:  \frac{1}{3} }

L.C.M of 2 and 3 = 6

So, ⇒\mathsf{ \frac{1 \times 3}{2 \times 3}  +  \frac{1 \times 2}{3 \times 2} }

⇒\mathsf{ \frac{3}{6}  +  \frac{2}{6} }

⇒\frac{5}{6}

Multiplication of fractions

To multiply one fraction by another, multiply the numerators for the numerator and multiply the denominators for its denominator and reduce the fraction obtained after multiplication into lowest term.

When any number or fraction is divided by a fraction, we multiply the dividend by reciprocal of the divisor. Let's consider a multiplication of a whole number by a fraction:

\mathsf{4 \times  \frac{3}{2}  =  \frac{4 \times 3}{2}  =  \frac{12}{2}  = 6}

Multiplication for \mathsf{ \frac{6}{5}  \: and \:  \frac{25}{3} } is done by the similar process

\mathsf{ =  \frac{6}{5}  \times  \frac{25}{3}  = 2 \times 5 \times 10}

Hope I helped!

Best regards!

5 0
3 years ago
Help me guyssss pleaseee
matrenka [14]

Answer:

a

Step-by-step explanation:

trust me i used to this all the time

3 0
3 years ago
Which polynomial is in standard form?
RoseWind [281]

<em>Answer</em><em>:</em><em> </em><em>1</em><em>1</em><em>x</em><em>^</em><em>3</em><em>-</em><em>6</em><em>x</em><em>^</em><em>2</em><em>+</em><em>5</em><em>x</em>

<em>to</em><em> </em><em>put</em><em> </em><em>the</em><em> </em><em>polynomial</em><em> </em><em>in</em><em> </em><em>standard</em><em> </em><em>form</em><em>,</em><em>we</em><em> </em><em>have</em><em> </em><em>to</em><em> </em><em>arrange</em><em> </em><em>it</em><em> </em><em>from</em><em> </em><em>highest</em><em> </em><em>power</em><em> </em><em>to</em><em> </em><em>lowest</em><em> </em><em>power</em><em>.</em>

<em>Well</em><em>,</em><em>I</em><em> </em><em>am</em><em> </em><em>not</em><em> </em><em>good</em><em> </em><em>at</em><em> </em><em>giving</em><em> </em><em>explanations</em><em>.</em><em>.</em><em>.</em>

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<h3><em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em></h3>

<em>~</em><em>P</em><em>r</em><em>a</em><em>g</em><em>y</em><em>a</em>

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