Answer:
B) 1
Step-by-step explanation:
Given:

We need to solve the given expression.
Now We know that when base of the exponents then the law of indices applied for the same.
Now According to Law of Indices.

On Solving the above expression we get;

Hence The Simplified form of given expression is 1.
Answer:
The answer is 9
Step-by-step explanation:
If you subtract 8-(-1) you would get 9.
Answer:
DE = 18
Step-by-step explanation:
Given that,
Point D is on line segment CE.
DE = x+10, CD=6 and CE=3x
We need to find the length of DE.
ATQ,
CE = CD + DE
Putting all the values,
3x = 6 + x+10
Taking like terms together
3x-x = 16
2x = 16
x = 8
DE = x+10
= 8+10
= 18
Hence, the length of DE is 18.
Answer:
This is the graph one
Step-by-step explanation:
A(-1,-4) -->A' (1,-4)
B(-3,-2) ---> B'(3,-2)
C(-1,2) ---> C(1,2)