Question

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Answer 1

Answer:

Step-by-step explanation:

A >

Divide both side by sin^2 x , and we get

Subtracting cosec^2 x from both sides we get

B>lets break tan θ into its components tan θ = sin θ / cos θ and cot θ = 1/ tan θ

Tan θ + cot θ=  Sin θ/cos θ + cos θ/ sin θ =  sin^2 θ + cos^2 θ  / sin θ cos θ= 1/ sin θ cos θ = sec θ cosec θ

Answer 2

Answer:

See below

Step-by-step explanation:

A > $Sin^{2} x + cos^{2} x = 1$

Divide both side by sin^2 x , and we get

$\frac{sin^2 x}{sin^2 x} + \frac{cos^2 x}{ sin^2 x} = \frac{1}{sin^2 x}$

$1+ cot^2 x= cosec^2 x$

Subtracting cosec^2 x from both sides we get

$Cosec^2 x - cot^2 x = 1$

B>lets break tan θ into its components tan θ = sin θ / cos θ and cot θ = 1/ tan θ

Tan θ + cot θ=  Sin θ/cos θ + cos θ/ sin θ =  sin^2 θ + cos^2 θ  / sin θ cos θ= 1/ sin θ cos θ = sec θ cosec θ