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s344n2d4d5 [400]
3 years ago
15

PLEASE HELP ME I WILL GIVE BRAINIEST IM STUDYING HELP A PERSON OUT NO SCAMMSSS>S>>S

Mathematics
1 answer:
ASHA 777 [7]3 years ago
7 0

Answer:

White

Step-by-step explanation:

20 divided by 4 = 5

White was spun 5 times.

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The equation for the pH of a substance is pH = –log[H+], where H+ is the concentration of hydrogen ions. Which equation models t
Elden [556K]
\bf \textit{Logarithm Cancellation Rules}
\\\\
log_a a^x = x\qquad \qquad \boxed{a^{log_a x}=x}\\\\
-------------------------------\\\\
pH=-log(H+)\qquad \stackrel{pH}{7.2}=-log(H+)\implies -7.2=log_{10}(H+)
\\\\\\
10^{-7.2}=10^{log_{10}(H+)}\implies 10^{-7.2}=H+\implies \cfrac{1}{10^{7.2}}=H+
3 0
2 years ago
Read 2 more answers
A = {1, 3, 5, 7, 9}<br> B = {2, 3, 5, 7}<br> What is A ∩ B?
Oksanka [162]

Answer:

  • It was {3,5,7}

6 0
3 years ago
Help me find the missing angles
Keith_Richards [23]

Answer:

  b) 105°

  d) 130°

Step-by-step explanation:

An external angle has the same measure as the sum of the remote internal angles.

b) ? = 25° +80° = 105°

d) ? = 35° +95° = 130°

_____

This should be fairly obvious if you consider that the adjacent internal angle together with the external angle totals 180°, and the adjacent internal angle together with the other two internal angles totals 180°.

If the two "remote" angles are A and B, and the adjacent internal angle is C, then we have in symbols ...

  A + B + C = 180° = ? + C

If we subtract C, then we find ...

  A + B = ? . . . . . . the fact we used above

8 0
3 years ago
Suppose N has a geometric distribution with parameter p. Derive a closed-form expression for E(N | N &lt;= k), k = 1,2,... Check
vfiekz [6]

Answer:

P(X= k) = (1-p)^k-1.p

Step-by-step explanation:

Given that the number of trials is

N < = k, the geometric distribution gives the probability that there are k-1 trials that result in failure(F) before the success(S) at the kth trials.

Given p = success,

1 - p = failure

Hence the distribution is described as: Pr ( FFFF.....FS)

Pr(X= k) = (1-p)(1-p)(1-p)....(1-p)p

Pr((X=k) = (1 - p)^ (k-1) .p

Since N<=k

Pr (X =k) = p(1-p)^k-1, k= 1,2,...k

0, elsewhere

If the probability is defined for Y, the number of failure before a success

Pr (Y= k) = p(1-p)^y......k= 0,1,2,3

0, elsewhere.

Given p= 0.2, k= 3,

P(X= 3) =( 0.2) × (1 - 0.2)²

P(X=3) = 0.128

3 0
2 years ago
Let f(x) = (5)^x+1 .Evaluate f (-3) without using a calculator
rewona [7]

Answer:

f\left(-3\right)=\frac{126}{125}

Step-by-step explanation:

Given

f\left(x\right)\:=\:\left(5\right)^x+1

Putting x = -3 to find f(-3)

f\left(-3\right)\:=\:\left(5\right)^{\left(-3\right)}+1

as

5^{-3}=\frac{1}{125}       ∵  \mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}

so

f\left(-3\right)=\frac{1}{125}+1

\mathrm{Convert\:element\:to\:fraction}:\quad \:1=\frac{1\cdot \:125}{125}

f\left(-3\right)=\frac{1\cdot \:\:125}{125}+\frac{1}{125}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

f\left(-3\right)=\frac{1\cdot \:\:125+1}{125}

f\left(-3\right)=\frac{126}{125}      ∵ 1\cdot \:125+1=126

Thus,

f\left(-3\right)=\frac{126}{125}

6 0
3 years ago
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