Sec x=1/cos x
Then:
7 cos x + 1=6 sec x
7 cos x + 1=6(1/cosx)
least common multiple=cos x
7 cos² x+cosx=6
7 cos² x + cosx -6=0
cos x=z
7z²+z-6=0
we solve this square equation:
z=[-1⁺₋√(1+168)]/14
z=(-1⁺₋13)/14
we have two solutions:
z₁=(-1-13)/14=-1
cos x=-1
x=arc cos (-1)=180º =π
Solution1=180º+2Kπ K∈Z
z₂=(-1+13)/14=12/14
cos x=12/14
x=arc cos (12/14)=31º
Solution2=31º+2kπ
Answer: solution1Usolution2= 31º+2Kπ U 180º+2Kπ; K∈Z
The answer is C<em>hristopher Columbus </em> I just took the test . hope this helps
It’s C. John Smith. It’s not Pocahontas because he’s would not be in touch with the king or care if the colonists lives or died. It’s not John Rolfe because he’s at a different colony. And it’s not Anne Burras Because she wasn’t even around when the colonies where just getting started.
People had to walk places and no one liked the whites if you were black
Group of leaders......................