Combinatorial Enumeration. That whole class was a rollercoaster ride of mind-blowing generating functions to prove crazy things. The exam had ridiculous questions like 'count the number of cactus trees with n vertices such that etc etc etc' and you'd do three pages of terrible terrible sums and algebra. Then your final answer would be something beautiful like n/2 and you'd breath a sigh of relief and thank the math gods.
Answer:
Step-by-step explanation:
There are no statements here
Answer: the required probability is 0.03516
Step-by-step explanation:
Given the data in the question;
let F represent dominant allele that causes fluffy fur and
f represent corresponding recessive allele that causes wiry fur
here are the possible genotypes and corresponding phenotypes;
FF = Fluffy fur
Ff = Fluffy fur
ff = Wiry fur
genotype of parents is Ff and Ff
and there cross will be; Ff x Ff
now Offspring will be;
F f
F FF Ff
f Ff ff
so the probability that the offspring will have fluffy fur = 3/4
and the probability that the offspring will have wiry fur = 1/4
The probability that the first 2 out of 4 offspring will have fluffy fur will be;
⇒ 3/4 × 3/4 × 1/4 × 1/4 = 0.03516
Therefore, the required probability is 0.03516
Answer:
sum is 1,2,4,8,16,32,64,128,256,512
