Answer:
1.3333333333333333 or 1 1/3
Step-by-step explanation:
What is the x?
Answer:
9.72
Step-by-step explanation:
s1 = 10.6383 ; s2 = 5.21289
x1 = 147.583 ; x2 = 136.417
n1 = 12 ; n2 = 12
df1 = n1 - 1 = 12 - 1 = 11
df2 = n2 - 1 = 12 - 1 = 11
The test statistic :
(x1 - x2) / sqrt[(sp²/n1 + sp²/n2)]
Pooled variance = Sp² = (df1*s1² + df2*s2²) ÷ (n1 + n2 - 2)
Sp² = ((11*10.6383) + (11*5.21289)) / 22 = 7.926
Test statistic, T* :
(147.583 - 136.417) / √(7.926 * (1/12 + 1/12))
11.166 / √(7.926 * (1/6)
11.166 / √1.321
11.166 / 1.1493476
T* = 9.7150766
Test statistic = 9.72
Answer:
Step-by-step explanation:
x≠ n*π, where n is an integer
because x/π can not be an integer
+ √6 = √9
The first step is to get by itself. We can do this by subtracting 
from each side, and simplifying 
= 3 -
Now we square both sides
5x = (3 - )²
Using the formula (a - b)² = a² -2ab + b², (3 - )² = 15 - 6
5x = 15 - 6
x = 
Answer:
16 cm
Step-by-step explanation:
Suppose that x is the original width. If that original width is enlarged by a scale factor 5/2 that means that x is multiplied by 5/2 and after that multiplication we obtained new width, 40 cm.
Therefore,
x*(5/2) = 40
We multiply the equation by 2 and obtain:
x*5 = 40*2
5x = 80
Now we divide the equation by 5 and obtain:
x = 80/5
x = 16
We obtained that x, the original width was 16 cm
