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Katen [24]
3 years ago
9

Use the distributive property to expand this equation please2/3 (18x + 6z)

Mathematics
1 answer:
natta225 [31]3 years ago
3 0

Answer:

12x + 4z

Step-by-step explanation:

Given: 2/3 (18x + 6z)

Multiply the fraction 2/3 into each term

(\frac{2}{3})*18x + (\frac{2}{3})*6z

\frac{36}{3}x + \frac{12}{3}z

12x + 4z

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\bf \begin{cases}
(n^4)^p=n^{12}\to &n^{4\cdot p}=n^{12}\to 4p=12
\\
&\qquad \uparrow \\
&\textit{same bases, thus}\\
&\qquad \downarrow 
\\
n^3\cdot n^q=n^6\to &n^{3+q}=n^6\to 3+q=6
\end{cases}
\\\\\\
thus\implies 
\begin{cases}
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\\\\
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\end{cases}
\\\\

\\\\
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\Delta KLJ\sim\DeltaNPM (AAA) Corresponding angles are congruent.

Therefore, the sides of the triangles are proportional:

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x=5

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\Delta PQR\cong\Delta STU (SAS)

If two sides and the included angle of one triangle are equal to the corresponding sides and angle of another triangle, the triangles are congruent.

Therefore we have the equation:

3y-2=y+4\qquad|+2\\\\3y=y+6\qquad|-y\\\\2y=6\qquad|:2\\\\y=3

The perimeter of △PQR:

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What is the measure of angle TSU?​
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