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3 years ago

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If there was only one government class, and Wes and Maureen were in that class of 38 students, what would be the probability tha

t both Wes and Maureen would be selected as the two students to go to Washington? Is this still an example of independent events

1 answer:

spayn [35]3 years ago

7 0

2/14and no it is not but 2 divided by 38 = 2

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Helpppppppp neededddd

ozzi

Answer:

Adam

Step-by-step explanation:

Speed is calculated with the formula distance over time.

Convert all measurements to the same unit: ft/s.

<u>Speed of Frank:</u>

d/t

=11/s

<u>Speed of Emily:</u>

d/t

=86/10

=8.6/s

<u>Speed of Adam: </u>

There are 5280 feet in a mile.

d/t

=5280/388

=13.6/s

<u>Speed of Noah:</u>

There are 60 seconds in a minute.

d/t

=600/60

=10/s

Adam runs the fastest because 13.6 > 11 > 10 > 8.6.

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3 years ago

In Raphael"s class there are 14 boys and 10 girls select whether each statment is true or false

Setler79 [48]

I can’t see the statements

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3 years ago

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Sarita showed the steps to solving the equation.

shtirl [24]

The option that explains Sarita's mistake is Sarita’s solution is correct. She made an error in her verification.

<h3>What was Sarita's mistake?</h3>

The given equation is: 5(x - 3) + 7(x + 4) = 73

In order to determine the value of x, take the following steps:

1. Apply the Distributive property:

5x - 15 + 7x + 28 = 73

2. Add similar terms together:

12x + 13 = 73

3. Combine similar terms:

12x = 73 - 13

4. Add similar terms

12x = 60

5. Divide both sides of the equation by 12

x = 60 / 12

x = 5

In order to verify the answer, substitute for x in the given equation :

5(5 - 3) + 7(5 + 4) = 73

5(2) + 7(9) = 73

10 + 63 = 73

73 = 73

Please find attached the complete question. To learn more about equations, please check: brainly.com/question/14446120

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1 year ago

The amount of time a passenger waits at an airport check-in counter is random variable with mean 10 minutes and standard deviati

Stolb23 [73]

Answer:

(a) less than 10 minutes

= 0.5

(b) between 5 and 10 minutes

= 0.5

Step-by-step explanation:

We solve the above question using z score formula. We given a random number of samples, z score formula :

z-score is z = (x-μ)/ Standard error where

x is the raw score

μ is the population mean

Standard error : σ/√n

σ is the population standard deviation

n = number of samples

(a) less than 10 minutes

x = 10 μ = 10, σ = 2 n = 50

z = 10 - 10/2/√50

z = 0 / 0.2828427125

z = 0

Using the z table to find the probability

P(z ≤ 0) = P(z < 0) = P(x = 10)

= 0.5

Therefore, the probability that the average waiting time waiting in line for this sample is less than 10 minutes = 0.5

(b) between 5 and 10 minutes

i) For 5 minutes

x = 5 μ = 10, σ = 2 n = 50

z = 5 - 10/2/√50

z = -5 / 0.2828427125

= -17.67767

P-value from Z-Table:

P(x<5) = 0

Using the z table to find the probability

P(z ≤ 0) = P(z = -17.67767) = P(x = 5)

= 0

ii) For 10 minutes

x = 10 μ = 10, σ = 2 n = 50

z = 10 - 10/2/√50

z = 0 / 0.2828427125

z = 0

Using the z table to find the probability

P(z ≤ 0) = P(z < 0) = P(x = 10)

= 0.5

Hence, the probability that the average waiting time waiting in line for this sample is between 5 and 10 minutes is

P(x = 10) - P(x = 5)

= 0.5 - 0

= 0.5

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3 years ago

Please answer this correctly without making mistakes

satela [25.4K]

Answer:

8940 table spoons and 2 teaspoons

Step-by-step explanation:

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