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KIM [24]
2 years ago
7

A snowstorm lasted for three days. During the storm, 8 inches of snow fell on the first day, 6 inches of snow fell on the second

day, and 9 inches of snow fell on the third day. Altogether, how many feet of snow fell during the three-day snowstorm? Use paper to show your work.
Mathematics
2 answers:
Lesechka [4]2 years ago
6 0

Answer:

23

Step-by-step explanation:

First you add 8+6 which equals 14.

Then you add 14+9 which equals 23.

So there fore your answer is 23!

Softa [21]2 years ago
3 0

Answer:

23 inches

Step-by-step explanation:

add all of the snow that fell together and you have your answer

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Pls help I dont know how to do this​
german

Answer:

  • 1. CE = 63
  • 2. x = 16

Step-by-step explanation:

Use proportions to solve.

Corresponding sides have same ratio.

<u>Question 1</u>

  • DE/EG = CE/EF
  • (6x + 3)/17 = (8x - 1)/21
  • 21(6x + 3) = 17(8x - 1)
  • 126x + 63 = 136x - 17
  • 10x = 80
  • x = 8
  • CE = 8*8 - 1
  • CE = 63

<u>Question 2</u>

  • KM/MD = KZ/ZH
  • (x + 8)/21 = 32/28
  • x + 8 = 21*8/7
  • x + 8 = 24
  • x = 24 - 8
  • x = 16
5 0
3 years ago
Can someone help me with the areas?
9966 [12]

Answer:

for 1. it is 99 and for 3. it is 343.75

Step-by-step explanation:

for 1. you have to just multiply the length with width

for 3. you have to add both bases (35+20) and multiply the height (55 x 12.5) to it and then divide it by 2 (687.5 / 2)

hope this helps! please heart <3

8 0
2 years ago
Read 2 more answers
Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean
Zinaida [17]

Answer:

E[R] = 99 Ω

\sigma_R = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, E[R] = \frac{a+b}{2}  = \frac{95+103}{2} = \frac{198}{2} = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333

Hence,

The standard deviation of resistance, \sigma_R = \sqrt{V(R)} = \sqrt5.333 = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

z_1 = \frac{102-99}{2.3094} = 1.299

z_2 = \frac{98-99}{2.3094} = -0.433

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

5 0
3 years ago
Evaluate the expression 3c – d for the given variable. d = -c + 7
s2008m [1.1K]
3c-d
3c-(-c+7)
3c+c-7
4c-7
Final answer: 4c-7
5 0
4 years ago
a cardboard box holds 31.25 cubic inches of creamy butter. The butter is molded into a square prism that is 5 inches long. How m
lesya [120]

Answer:

62.5 \:in^2

Step-by-step explanation:

Volume of the butter in the cardboard = 31.25 cubic inches

Length of the Molded Square Prism =5 Inches

Let the length of the square cross sectional area = x

Volume of the Prism=x^2l

Since l=5 Inches

5x^2=31.25\\x^2=6.25\\x=2.5\: Inches

Next, we determine the surface area of the New Cardboard box to be made.

Length of the Cardboard Box=5 Inches

Length of the square cross sectional area = 2.5 Inches

Total Surface Area=2(x^2+xl+xl)=2(x^2+2xl)

=2(2.5^2+2(2.5)(5))\\=2(6.25+25)\\=2*31.25\\=62.5 \:in^2

Therefore, 62.5 \:in^2 of cardboard is needed,

4 0
3 years ago
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