The probability that the train will be there when Alex arrives is 5/18
If Alex arrives at any time after 1.20pm the chances that train will be there is 1/3.
However if alex arrives at 1.00pm exactly there is no chance the train will be arrive there.
The probability that the train will be there increase linearly to 1/3 as alex's arrival time moves from 1.00pm to 1.20pm.
By arranging the probabilities over the first 20 minutes to get a 1/6 chance the train will be there if alex arrives between 1.00pm to 1.20pm
we get the final answer by
=1/3( 1/6 + 1/3 + 1/3)
=5/18
So, the probability that the train will be there when Alex arrives is 5/18
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80. there's no mathematical equations, also there's nothing to compare
Answer:divide the opposite sides, by the length of the hypotenuse. To get the cosine, divide the length of the adjacent side,by the length of the hypotenuse.
Step-by-step explanation:
divide the opposite sides, by the length of the hypotenuse. To get the cosine, divide the length of the adjacent side,by the length of the hypotenuse.
The answer is 88 because if you add 5+3 and then multiply by 11, you would equal out to 88 dogs and cats
