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kakasveta [241]
3 years ago
14

Silver iodide powder has been used as an antiseptic and as an agent to seed clouds for rain. Silver iodide is 45.9% silver by ma

ss. If you separate a 50.0-g sample of silver iodide into its elements, silver and iodine, how much silver would you have?
Chemistry
1 answer:
Dahasolnce [82]3 years ago
6 0

Answer:

22.95g

Explanation:

Given parameters:

Percentage by mass of silver in silver iodide  = 45.9%

Mass of silver iodide given  = 50g

Unknown:

Mass of silver in silver iodide  = ?

Solution:

The formula of the compound is;

 Silver iodide  = AgI

       Since the percentage by mass of silver in the compound is 45.9%;

 Mass of silver  = percentage by mass of silver x mass of AgI

 Mass of silver  = \frac{45.9}{100} x 50  = 22.95g

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Which of the following forces is responsible for accretion?
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Answer:

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Explanation:

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8 0
3 years ago
16.0 grams of oxygen gas reacted with 80.0 grams nitrogen monoxide gas producing 25.0 grams of nitrogen dioxide gas in the lab.
Anon25 [30]

Answer:

Limiting reactant  = O₂

Excess reactant = NO

Theoretical yield of NO₂ = 46 g

Mass of excess reactant = 30 g

<h3 />

Explanation:

O₂ + 2NO → 2NO₂

Mole ratio for the reaction is;

1 : 2 → 2

mass of O₂ = 16 g

mass of NO = 80 g

mass of NO₂ = 25 g

molecular weight  of O₂ = 32 g/mol

molecular weight  of NO = 30 g/mol

molecular weight  of NO₂ = 46 g/mol

molar mass of O₂ = mass ÷ molecular weight = 16 g ÷ 32 g/mol = 0.5 mol

molar mass of NO = mass ÷ molecular weight = 80 g ÷ 30 g/mol = 2.67 mol

Since, 1 mole of O₂ requires 2 moles of NO for the combustion reaction, 0.5 mole shall require 1 mole of NO for the reaction. Thus, O₂ is the limiting reactant and NO is the excess reactant as it has an excess of 2.67 mol - 1 mol = 1.67 mol.

<h3>Theoretical yield of NO₂</h3><h3 />

1 mole of O₂ shall yield 2 moles of NO₂

Thus, 0.5 mole of O₂ shall yield 1 mole of NO₂

mass of NO₂ = molecular weight * molar mass = 46 g/mol * 1 mole = 46 g

<h3>Mass of Excess Reactant</h3>

1 mole of O₂ shall react with 2 moles of NO

Thus, 0.5 mole of O₂ shall yield 1 mole of NO

mass of NO = molecular weight * molar mass = 30 g/mol * 1 mole = 30 g

5 0
3 years ago
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4 years ago
Q 11.8: Exposure of 2-methyl-2-butene to oxymercuration-demercuration conditions provides which product?
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Answer:

Exposure of 2-methyl-2-butene to oxymercuration-demercuration conditions provides 2-methyl-2-butanol.

Explanation:

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3 years ago
Consider the following substances: hydrogen gas (H2), carbon dioxide (CO2), Sulfur (S8). neon (Ne) and propane (C3H8). Which sub
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