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3 years ago

Y=(3x+7)(8x-5). Find the derivative

Mathematics

2 answers:

Serhud [2]3 years ago

7 0

Step-by-step explanation:

$y = {24x}^{2} - 15x + 56x - 35$

$y = 24x {}^{2} + 41x - 35$

$\frac{dy}{dx} = 48x + 41$

lozanna [386]3 years ago

6 0

Answer:

Step-by-step explanation:

use uv rule= uv'+vu'

u=3x+7

u'=3+0=3

v=8x-5

v'=8-0=8

uv= (3x+7)(8)+(8x-5)(3)

=24x+56+24x-15

=48x+41

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Compare |-2/5| and |-3/8|

nasty-shy [4]

Answer:

2/5 and 3/8

2/5 is greater than 3/8

Step-by-step explanation:

Those parallel lines mean absolute value which means no signs no positive nor negative.

8 0

3 years ago

A math class consists of 25 students, 14 female and 11 male. Three students are selected at random to participate in a probabili

vovangra [49]

Answer:

(a) The probability that a male is selected, then two females is 0.4352.

(b) The probability that a female is selected, then two males is 0.3348.

(c) The probability that two females are selected, then one male is 0.4352.

(d) The probability that three males are selected is 0.0717.

(e) The probability that three females are selected is 0.1583.

Step-by-step explanation:

We are given that a math class consists of 25 students, 14 female and 11 male. Three students are selected at random to participate in a probability experiment.

(a) The probability that a male is selected, then two females is given by;

Number of ways of selecting a male from a total of 11 male = $^{11}C_1$

Number of ways of selecting two female from a total of 14 female = $^{14}C_2$

Total number of ways of selecting 3 students from a total of 25 = $^{25}C_3$

So, the required probability = $\frac{^{11}C_1 \times ^{14}C_2}{^{25}C_3}$

= $\frac{\frac{11!}{1! \times 10!} \times \frac{14!}{2! \times 12!} }{\frac{25!}{3! \times 22!} }$ { $\because ^{n}C_r = \frac{n!}{r! \times (n-r)!}$ }

= $\frac{1001}{2300}$ = 0.4352

(b) The probability that a female is selected, then two males is given by;

Number of ways of selecting a female from a total of 14 female = $^{14}C_1$

Number of ways of selecting two males from a total of 11 male = $^{11}C_2$

Total number of ways of selecting 3 students from a total of 25 = $^{25}C_3$

So, the required probability = $\frac{^{14}C_1 \times ^{11}C_2}{^{25}C_3}$

= $\frac{\frac{14!}{1! \times 13!} \times \frac{11!}{2! \times 9!} }{\frac{25!}{3! \times 22!} }$ { $\because ^{n}C_r = \frac{n!}{r! \times (n-r)!}$ }

= $\frac{770}{2300}$ = 0.3348

(c) The probability that two females is selected, then one male is given by;

Number of ways of selecting two females from a total of 14 female = $^{14}C_2$

Number of ways of selecting one male from a total of 11 male = $^{11}C_1$

Total number of ways of selecting 3 students from a total of 25 = $^{25}C_3$

So, the required probability = $\frac{^{14}C_2 \times ^{11}C_1}{^{25}C_3}$

= $\frac{\frac{14!}{2! \times 12!} \times \frac{11!}{1! \times 10!} }{\frac{25!}{3! \times 22!} }$ { $\because ^{n}C_r = \frac{n!}{r! \times (n-r)!}$ }

= $\frac{1001}{2300}$ = 0.4352

(d) The probability that three males are selected is given by;

Number of ways of selecting three males from a total of 11 male = $^{11}C_3$

Total number of ways of selecting 3 students from a total of 25 = $^{25}C_3$

So, the required probability = $\frac{^{11}C_3}{^{25}C_3}$

= $\frac{ \frac{11!}{3! \times 8!} }{\frac{25!}{3! \times 22!} }$ { $\because ^{n}C_r = \frac{n!}{r! \times (n-r)!}$ }

= $\frac{165}{2300}$ = 0.0717

(e) The probability that three females are selected is given by;

Number of ways of selecting three females from a total of 14 female = $^{14}C_3$

Total number of ways of selecting 3 students from a total of 25 = $^{25}C_3$

So, the required probability = $\frac{^{14}C_3}{^{25}C_3}$

= $\frac{ \frac{14!}{3! \times 11!} }{\frac{25!}{3! \times 22!} }$ { $\because ^{n}C_r = \frac{n!}{r! \times (n-r)!}$ }

= $\frac{364}{2300}$ = 0.1583

8 0

3 years ago

Read 2 more answers

liberstina [14]

The answer is 3 point g

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3 years ago

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(4/5)x - 8 = (5/3)x - 7 Find x

Dafna1 [17]

Answer:

-15/13

Step-by-step explanation:

4/5x - 8 = 5/3x - 7

4x - 40 = 25/3x - 35

12x - 120 = 25x - 105

-13x = 15

x = -15/13

Topic: Fractions

If you like to venture further, feel free to check out my insta (learntionary). It would be best if you could give it a follow. I'll be constantly posting math tips and notes! Thanks!

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3 years ago

4. a. If the original lengths are multiplied by 2, what are the new coordinates? *

Lapatulllka [165]

divide

Step-by-step explanation:

But i think I know what you need to do so first count the graph like see where it is pointed at then divide and u get ur answer Again im not sure but maybe

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3 years ago