All categories

3 years ago

What is the step for 6b+8=-4

Mathematics

1 answer:

VMariaS [17]3 years ago

7 0

Answer

Step-by-step explanation:

6b+8=-4

subtract 8 from both sides

6b=-4-8

solve -4-8

and get, 6b=-12

divid by 6

b=-2

You might be interested in

22. Find the perimeter and area.

zmey [24]

Answer:

Part 22) The area is $A=15a^3b^6\ units^2($ and the perimeter is $P=10a^2b^4+6ab^2\ unit$

Part 24) The area is $A=16m^3n\ units^2$ and the perimeter is $P=24mn\ units$

Part 26) The area is equal to $A=9\pi x^6y^{2}\ units^2$

Step-by-step explanation:

Part 22) Find the perimeter and area

step 1

The area of a rectangle is equal to

$A=LW$

we have

$L=5(a^2)(b^4)\ units$

$W=3(a)(b^2)\ units$

Remember that

When multiply exponents with the same base, adds the exponents and maintain the base

substitute in the formula

$A=(5(a^2)(b^4))(3(a)(b^2))$

$A=15a^3b^6\ units^2$

step 2

The perimeter of a rectangle is equal to

$P=2(L+W)$

we have

$L=5(a^2)(b^4)\ units$

$W=3(a)(b^2)\ units$

substitute in the formula

$P=2(5(a^2)(b^4)+3(a)(b^2))$

$P=10a^2b^4+6ab^2\ unit$

Part 24) Find the perimeter and area

step 1

The area of triangle is equal to

$A=\frac{1}{2}bh$

where

$b=8mn\ units$

$h=4m^2\ units$

Remember that

When multiply exponents with the same base, adds the exponents and maintain the base

substitute the given values

$A=\frac{1}{2}(8mn)(4m^2)$

$A=16m^3n\ units^2$

step 2

Find the perimeter

I will assume that is an equilateral triangle (has three equal length sides)

The perimeter of an equilateral triangle is

$P=3b$

where

$b=8mn\ units$

substitute

$P=3(8mn)$

$P=24mn\ units$

Part 26) Find the area

The area of a circle is equal to

$A=\pi r^{2}$

where

$r=3x^3y\ units$

Remember the property

$(a^{m})^{n}=a^{m*n}$

substitute in the formula the given value

$A=\pi (3x^3y)^{2}$

$A=9\pi x^6y^{2}\ units^2$

6 0

3 years ago

Which one?????? i need help

borishaifa [10]

<h3>Given</h3>

x + 2 ≥ 6

the graph for the solution

<h3>Solution</h3>

We can solve for x by subtacting 2 from both sides of the inequality.

... x + 2 -2 ≥ 6 -2

... x ≥ 4 . . . . . . . . . . simplify

The answer is read, "x is greater than or equal to 4." This means the solution is those real numbers that are to the right of 4 on the number line, and including 4 on the number line. Numbers to the left of 4 are <em>not included</em>. The inclusion of the number 4 is shown by putting a solid dot there (not an open circle).

The appropriate choice is the 3rd one.