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victus00 [196]
3 years ago
9

Write each absolute value in a box to show the order from least to greatest.

Mathematics
2 answers:
Genrish500 [490]3 years ago
8 0

Answer:

From least to greatest: -12 -8 -2 5 11

Step-by-step explanation:

Please mark brainliest have a good day and i hope i helped :)

alisha [4.7K]3 years ago
5 0

Answer:

(11)=(3)-(1)+(6)=6

Step-by-step explanation:

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I need to know question 14 of this photo pls
Vladimir79 [104]
Needed discount= 350-220= 130

needed dicount %=(130/350)*100=37.14 %( this is minimum discount needed)

since only multiples of 5% are allowed ,the closest minimum discount is 40%.
7 0
3 years ago
What is the distance around a figure?
podryga [215]

The distance around a figure is called the perimeter.

Hope this helps :)

4 0
3 years ago
Read 2 more answers
Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br
aliya0001 [1]

Answer:

A=1500-1450e^{-\dfrac{t}{250}}

Step-by-step explanation:

The large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved.

Volume = 500 gallons

Initial Amount of Salt, A(0)=50 pounds

Brine solution with concentration of 2 lb/gal is pumped into the tank at a rate of 3 gal/min

R_{in} =(concentration of salt in inflow)(input rate of brine)

=(2\frac{lbs}{gal})( 3\frac{gal}{min})\\R_{in}=6\frac{lbs}{min}

When the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

Concentration c(t) of the salt in the tank at time t

Concentration, C(t)=\dfrac{Amount}{Volume}=\dfrac{A(t)}{500}

R_{out}=(concentration of salt in outflow)(output rate of brine)

=(\frac{A(t)}{500})( 2\frac{gal}{min})\\R_{out}=\dfrac{A}{250}

Now, the rate of change of the amount of salt in the tank

\dfrac{dA}{dt}=R_{in}-R_{out}

\dfrac{dA}{dt}=6-\dfrac{A}{250}

We solve the resulting differential equation by separation of variables.  

\dfrac{dA}{dt}+\dfrac{A}{250}=6\\$The integrating factor: e^{\int \frac{1}{250}dt} =e^{\frac{t}{250}}\\$Multiplying by the integrating factor all through\\\dfrac{dA}{dt}e^{\frac{t}{250}}+\dfrac{A}{250}e^{\frac{t}{250}}=6e^{\frac{t}{250}}\\(Ae^{\frac{t}{250}})'=6e^{\frac{t}{250}}

Taking the integral of both sides

\int(Ae^{\frac{t}{250}})'=\int 6e^{\frac{t}{250}} dt\\Ae^{\frac{t}{250}}=6*250e^{\frac{t}{250}}+C, $(C a constant of integration)\\Ae^{\frac{t}{250}}=1500e^{\frac{t}{250}}+C\\$Divide all through by e^{\frac{t}{250}}\\A(t)=1500+Ce^{-\frac{t}{250}}

Recall that when t=0, A(t)=50 (our initial condition)

50=1500+Ce^{-\frac{0}{250}}50=1500+Ce^{0}\\C=-1450\\$Therefore the amount of salt in the tank at any time t is:\\A=1500-1450e^{-\dfrac{t}{250}}

4 0
3 years ago
pregunta de matematica conteste verdadero o falso el siguiente enunciado : En una razón escrita como fracción el numerador recib
Fantom [35]

Answer: falso.

Step-by-step explanation:

En una fracción, el antecedente siempre es el dividendo (también llamado numerador) y el consecuente es el divisor (también llamado denominador)

Es decir, de momento la parte de: "En una razón escrita como fracción el numerador recibe el nombre de antecedente y el denominador recibe el nombre de consecuente el denominador..."

Es verdadera.

El problema en el enunciado es:

"... el denominador puede ser cualquier número"

Esta parte es falsa, el denominador no puede ser 0.

Entonces el denominador no puede ser cualquier número, y así podemos concluir que el enunciado:

" En una razón escrita como fracción el numerador recibe el nombre de antecedente y el denominador recibe el nombre de consecuente el denominador puede ser cualquier número"

Es falso.

"

7 0
3 years ago
How many pennies equal one million dollars?write your answer in scientific notation.
lisabon 2012 [21]
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7 0
3 years ago
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