3 years ago

In the coordinate plane, choose the graph with the conditions given. x = -3

1 answer:

5 0

You have not given any graphs to choose from but x=-3 would be the graph that has a vertical line running through every point that has -3 as an x coordinate and would cross the x axis (the horizontal axis) at -3

You might be interested in

3(x-4)^2=27 solution

satela [25.4K]

Answer:

x = 11

x = 7

Step-by-step explanation:

divide each side by 3 to get:

(x-4)² = 9

(x-4)² is the difference of two squares and has these factors:

(x+2)(x-2) = 9

x + 2 = 9; x = 7

x - 2 = 9; x = 11

8 0

3 years ago

suppose that the x-intercepts of the graph of y=f(x) are 4 and 8. What are the x-intercepts of the graph of y=f(x+5)

lesya692 [45]

Find what the 5 is and times the f with x

7 0

3 years ago

Please help me solve this problem. Whoever answers right first will be brainliest

Phantasy [73]

Answer:

100 waffles

Step-by-step explanation:

5 0

2 years ago

If 2a + b = 13 and 3c-6a = 5, what is the value of b + c?

ElenaW [278]

Step-by-step explanation:

Solve the first eqn for b, b=13–2*a, and the 2nd for c, c=(6*a+5)/3. Then

b+c=13–2*a+(6*a+5)/3=13–2*a+2*a+5/3=44/3. We see that b+c has a definite value because the terms in a cancel.

7 0

3 years ago

Read 2 more answers

an Archer shoots an arrow into the air such that its height at any time T is given by the function H (t) = -16t^2+ Kt + 3 if the

Sunny_sXe [5.5K]

$\begin{gathered} H(t)=-16t^2+kt+3 \\ At\text{ maximum height, final velocity = 0} \end{gathered}$

4 0

1 year ago