First things first: all quadrilateral have an interior of 360⁰. With that info, you can do your exercice.
the first one:
the angle P =90⁰
the angle Q=90⁰
So you do the deduction:
360⁰-90⁰-90⁰-65⁰= 115⁰
the second one:
the angle F=60⁰
so you do the same thing as number one:
360⁰-60⁰-60⁰= 240⁰
240⁰/2= 120⁰
Voilà!
I think 15 I am not 100 percent on that
I hope this helps you
h (x)= -2x+4x-8
h (x)=2x-8
The following are the answers to
the questions presented:
Part 1:
Vertex: <span>(<span><span>−3</span>/ 2</span>,<span> 11/2</span>)</span>
Axis of
symmetry = x = -3/2
Domain = all
real numbers
Range = <span>y </span><span>≤ </span>11/2
Part 2:
A quadratic equation is symmetrical around its vertex. The
equation for the axis of symmetry is x = -3/2 since the equation is in terms of
x. Since no value of x is undefined, then the domain of the equation is clearly
all real numbers. Since the value of “a” is negative, then that means the y
coordinate of the vertex is the maximum value so the range will never get above
11/2. I am hoping that these answers have satisfied your queries and it
will be able to help you in your endeavors, and if you would like, feel free to
ask another question.
