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koban [17]
3 years ago
7

30° + 180° (2n + 1), its radian measure is equivalent to?​

Mathematics
1 answer:
Nuetrik [128]3 years ago
7 0

Answer:

Example: Find the radian measure of the angles −70° and 120°.

Solution: To find the radian measure of −70° we multiply −70 by the conversion factor /180. We get

Similarly, for 120° we obtain

Note that when we write an angle as a fractional amount of , for example 2/3 times  we write the result either as the numerator times  divided by the denominator or as the fraction times . So the two values

are equivalent ways of writing the same number. You will see both methods used in the text and in the exercises.

Example: Find the degree measure of /12.

Solution: The conversion factor for going from radians to degrees is 180/. We get

and so the radian measure of /12 is 15°.

Step-by-step explanation:

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Answer:

$9.00

Step-by-step explanation:

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1. Since it was 15% discount, that means you have to solve 15% of 60, which is equivalent to 0.15 x 60.

2. Since the product of 0.15 and 60 is 9, then 9 is your answer.

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Answer:

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At a Psychology final exam, the scores are normally distributed with a mean 73 points and a standard deviation of 10.6 points. T
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Answer:

The score that separates the lower 5% of the class from the rest of the class is 55.6.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

\mu = 73, \sigma = 10.6

Find the score that separates the lower 5% of the class from the rest of the class.

This score is the 5th percentile, which is X when Z has a pvalue of 0.05. So it is X when Z = -1.645.

Z = \frac{X - \mu}{\sigma}

-1.645 = \frac{X - 73}{10.6}

X - 73 = -1.645*10.6

X = 55.6

The score that separates the lower 5% of the class from the rest of the class is 55.6.

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