What is the answer?❤️

2.36 to the nearest whole number. Help please

melisa1 [442]

Answer:

2

Step-by-step explanation:

Since if it's 5 or higher you go up but if it's 4 or lower you stay the same. And since 2.36 doesn't have the .5 it would round to 2

7 0

3 years ago

Read 2 more answers

in the lab, Tammy has two solutions thta contain alcohol and is mixing them with each other. She use twice as much Solution A as

Dmitry_Shevchenko [17]

Answer:

She uses 200 milliliters of solution B

Step-by-step explanation:

Notice that there are two unknowns in this problem: 1) the amount of solution A that is being used, and 2) the amount of solution B being used. We can name such unknowns with letters to facilitate our work:

Amount of solution A to be used = A

Amount of solution B to be used = B

So, since we need to find two unknowns, we need to create a system of two equations to solve them.

Our first equation can be obtained from the sentence: "She uses twice as much Solution A as Solution B," which written in mathematical form is:

A = 2 B

The second equation we can build from the information of the amount of alcohol in each solution that combined will add up to 104 milliliters of alcohol in the mixture. Knowing the percent of alcohol in each solution, we can write an equation for the amount of alcohol:

0.19 A + 0.14 B = 104

Now we can use our first equation to substitute A in terms of B in the second equation:

0.19 (2 B) + 0.14 B = 104

0.38 B + 0.14 B = 104

0.52 B = 104

B = 104 / 0.52

B = 200 milliliters

4 0

3 years ago

0.06 or 0.06666666666 As a fraction

garik1379 [7]

0.06 = 6/100
When simplified, that's 3/50 .

0.06666666666 = 6,666,666,666/10,000,000,000
When simplified, that's 3,333,333,333/5,000,000,000 .

8 0

3 years ago

Maricella solves for x in the equation 4x-2(3x-4)+4=-x+3(x+1)+1. She begins by adding –4 + 4 on the left side of the equation an

Elodia [21]

Maricella’s strategy is incorrect as the values added on the left and right side of the equation changes the original equation $4x-2(3x-4)+4=-x+3(x+1)+1$ to $4x-2(3x-4)+4=-x+3(x+1)+3$ .

Further explanation:

Maricella begin by adding $-4+4$ on the left side of the equation and $1+1$ on the right side of the equation $4x-2(3x-4)+4=-x+3(x+1)+1$ .

The value added on the left is equal to zero so it does not change the equation but the value added on the right is 2, a non-zero digit so it changes the equation as shown below.

$4x-2(3x-4)+4-4+4=-x+3(x+1)+1+1+1\\4x-2(3x-4)+4+0=-x+3(x+1)+1+2\\4x-2(3x-4)+4=-x+3(x+1)+3$

Therefore, the strategy used by Maricella will change the equation and so the solution of the equation will be incorrect.

One way of solving such a linear equation is by adding or subtracting the required value on each side of the equation. and then simplifying the further equation.

Similarly, the other way to solve any linear equation is by separating the variable terms on one side of the equation and constant terms on the other side of the equation.

After this simplify the linear equation to obtain the solution of the equation for $x$ .

Whereas Maricella’s strategy fails to solve the equation $4x-2(3x-4)+4=-x+3(x+1)+1$ since the values added and subtracted in the equation changes the original equation completely.

Learn more:

1. Linear equation application brainly.com/question/2479097

2. To solve one variable linear equation brainly.com/question/1682776

3. Binomial and trinomial expression brainly.com/question/1394854

Answer details

Grade: Middle school

Subject: Mathematics

Chapter: Linear equation

Keywords: equation, linear equation, Maricella, right side, left side, strategy, solve for $x$ , adding, subtracting, variable, constant, solution of the equation, value, original equation, variable terms, constant terms.

4 0

2 years ago

Read 2 more answers

Plz help............................

Natasha2012 [34]

1.) Factor 9u^2-12u
$\frac{3u(3u-4)}{3u}$

2.) Cancel any common factors (in bold will be the terms eliminated)
$\frac{3u(3u-4)}{3u}$

Final answer is: 3u-4

Therefore, the answer is C. 3u-4

5 0

3 years ago