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astraxan [27]
3 years ago
10

A cube is numbered 1 through 6. If the cube is rolled twice, how many of the possible outcomes will have two even

Mathematics
1 answer:
victus00 [196]3 years ago
3 0

Answer:

B.)

9

Step-by-step explanation:

Hope this helps:)

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Alejandra was working on an animal report for school. She worked on it for 4 hours in a week. How many hours did she work on the
Mandarinka [93]

Answer: 0.57 hours each day or 34.28 minutes each day.

Step-by-step explanation:

1. You know that:

-Alejandra worked on the animal report for school for 4 hours in a week.

- A week has seven days.

2. Therefore, to calculate the number of hours she worked on the project each day (which you can call x), you can divide the number of hours  worked on in a week by 7 days.

3. Therefore, you obtain the following result:

x=\frac{4hours}{7day}\\x=0.57\ hours/day

Multiply the result by 60 to obtain the time in minutes, then:

x=34.28\ minutes

3 0
4 years ago
Rebecca and Tracy are cutting strips of fabric to make a quilt. Each strip of fabric needs to be 1/3 of a foot long. They have 1
Deffense [45]

48 strips of fabric.

6 0
3 years ago
Which represents the solution of the graphed system of equations, y=x^2-2x and y=-2x-1
elena55 [62]

Answer:

x = √(-1) = i

Since the value of √(-1) is not real.

The system has no real solution.

Step-by-step explanation:

The solution to the system of equations is at the point where they intercept each other.

y1 = y2

For the given equation;

y=x^2-2x and y=-2x-1

To get the where they intercept, we will equal both equations;

y=x^2-2x = -2x-1

x^2 - 2x = -2x - 1

x^2 - 2x + 2x + 1 =0

x^2 +1 = 0

x^2 = -1

x = √(-1) = i

Since the value of √(-1) is not real.

The system has no real solution.

6 0
4 years ago
Hellllllllllllppppppppp
const2013 [10]
I can help you. What is your question? Can you tell me?
5 0
4 years ago
Integrate [0, 1/2] xcos(pi*x).
elena-14-01-66 [18.8K]
To answer your question, this could be the possible answer and i hope you understand and interpret it correctly:
<span>[Integrate [0, 1/2] xcos(pi*x
let u=x so that du=dx
 and v=intgral cos (xpi)dx
        v=(1/pi)sin(pi*x)
 integration by parts
uv-itgral[0,1/2]vdu just plug ins
 (1/pi)sinpi*x]-(1/pi)itgrlsin(pi*x)dx from 0 to 1/2
(1/pi)x sinpi*x - (1/pi)[-(1/pi) cos pi*x] from 0 to 1/2
 =(1/2pi)+(1/pi^2)[cos pi*x/2-cos 0]
=1/2pi - 1/2pi^2
=(pi-2)/2pi^2 ans</span>
3 0
3 years ago
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