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Answer:
23 males and 12 females
Step-by-step explanation:
x = # of females
y = # of males
x + y = 35
x + x + 11 = 35
2x + 11 =35 (SUBTRACT 11 FROM BOTH SIDES)
2x = 24 (DIVIDE BOTH SIDES BY 2)
x = 12 females
x + y =35
12 + y = 35 (SUBTRACT 12 FROM BOTH SIDES)
y = 23 males
23 males + 12 females = 35 students
In order to have infinitely many solutions with linear equations/functions, the two equations have to be the same;
In accordance, we can say:
(2p + 7q)x = 4x [1]
(p + 8q)y = 5y [2]
2q - p + 1 = 2 [3]
All we have to do is choose two equations and solve them simultaneously (The simplest ones for what I'm doing and hence the ones I'm going to use are [3] and [2]):
Rearrange in terms of p:
p + 8q = 5 [2]
p = 5 - 8q [2]
p + 2 = 2q + 1 [3]
p = 2q - 1 [3]
Now equate rearranged [2] and [3] and solve for q:
5 - 8q = 2q - 1
10q = 6
q = 6/10 = 3/5 = 0.6
Now, substitute q-value into rearranges equations [2] or [3] to get p:
p = 2(3/5) - 1
p = 6/5 - 1
p = 1/5 = 0.2
