A macrophage may engulf a pathogen by endocytosis, which involves the reorganization of actin microfilaments in the membrane and microtubules in the cytoskeleton.
<h3>What is endocytosis?</h3>
Endocytosis is a cellular process by which a cell can absorb materials from the surrounding medium, such as viruses and bacteria in the case of macrophages.
Microfilaments and microtubules are proteins that form part of the cytoskeleton and dynamic conformational changes of them are associated with the cytoskeletal rearregement during the phagocytic process.
The actin microfilaments in the membrane and microtubules in the cytoskeleton form part of the process of endocytosis because they need to reorganize during cell movement.
In conclusion, a macrophage may engulf a pathogen by endocytosis, which involves the reorganization of actin microfilaments in the membrane and microtubules in the cytoskeleton.
Learn more about actin filaments here:
brainly.com/question/13777481
#SPJ1
<span>Composition. (We use the crust-mantle-core terminology to describe differences in chemical composition in Earth's interior. We use the lithosphere- asthenosphere terminology to describe differences the physical state and behavior. Note that the boundaries between layers with different compositions do not occur at the same depths as the boundaries between layers with different physical properties. For example, there is a change in composition when passing from crust into mantle. But there is no change in physical state or behavior at this boundary- the uppermost part of the mantle behaves in the same way that the crust does because it is still far enough below its melting temperature to be a rigid, brittle solid. The transition to a softer, more pliable solid occurs further down within the mantle and this change in behavior occurs with no change in composition.)</span>
Answer:
its A and D
D) #recombinant=116+601+4+2+113+625=1462
#nonrecombinant=2538+2708=5246
RF=R/(N+R)=1462/6708=0.2
E) I=1-Q
I-interference
Q-coefficient of coincidence
Q=O2Xo/E2xo(2xo-double crossovers)
O2xo=6
P=(distance from C1 to Sh/100)*(distance from Sh to Wx/100)
=(3.38/100)*(18.28/100)=0.006
E2xo=0.006*6708=40.248
Q=6/40.248=0.15
I=1-0.15=0.85