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Advocard [28]
3 years ago
14

I NEED HELP PLEASEEE ASAP

Mathematics
1 answer:
nikklg [1K]3 years ago
8 0
2) x= -8
3) y= -3
4) c= -2
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Find the area of a circle with a radius of 3
ExtremeBDS [4]

Answer: 28.27

Step-by-step explanation: first multiply the radius by itself 3 times 3 = 9

then take 9 and multiply it by 3.14 which is 28.27

hope this helps mark me brainliest

7 0
3 years ago
Read 2 more answers
What is the equation of a circle whose radius is 16 units and center is at (2,-5)?
STatiana [176]

Answer:

  • The general equation of the circle is
  • ( {x - a})^{2}  +  ({y - b})^{2}  =  {r}^{2}  \\ therefore \:  we \: \: have \:  \\ ( {x - 2})^{2}  + (y - ( - 5)) {}^{2}  =  ({16})^{2}  \\  ({x - 2})^{2}  + ( {y + 5})^{2}  = 256
  • HOPE THIS HELPS!
8 0
2 years ago
I need help with this question
nikdorinn [45]
The area of each triangular face is
.. A = (1/2)*b*h
.. Aside = (1/2)*(6 cm)*(5 cm) = 15 cm^2

The area of the triangular base is
.. Abase = ((√3)/4)*s^2 = (√3)/4*(6 cm)^2 = 9√3 cm^2

The total surface area is the base area plus the area of the three sides.
.. Atotal = Abase + 3*Aside
.. = 9√3 cm^2 +3*15 cm^2
.. = (45 +9√3) cm^2
.. ≈ 60.6 cm^2


Actually, there's an error in the picture. The height of the side should be 4, and the length of the edge should be 5. Making that adjustment, the total area is 51.6 cm^2.

It is hard to tell what is intended. Not all answers are showing, so we can't "reverse-engineer" the problem from the answers.
7 0
3 years ago
A random variableX= {0, 1, 2, 3, ...} has cumulative distribution function.a) Calculate the probability that 3 ≤X≤ 5.b) Find the
olchik [2.2K]

Answer:

a) P ( 3 ≤X≤ 5 ) = 0.02619

b) E(X) = 1

Step-by-step explanation:

Given:

- The CDF of a random variable X = { 0 , 1 , 2 , 3 , .... } is given as:

                    F(X) = P ( X =< x) = 1 - \frac{1}{(x+1)*(x+2)}

Find:

a.Calculate the probability that 3 ≤X≤ 5

b) Find the expected value of X, E(X), using the fact that. (Hint: You will have to evaluate an infinite sum, but that will be easy to do if you notice that

Solution:

- The CDF gives the probability of (X < x) for any value of x. So to compute the P (  3 ≤X≤ 5 ) we will set the limits.

                   F(X) = P ( 3=

- The Expected Value can be determined by sum to infinity of CDF:

                   E(X) = Σ ( 1 - F(X) )

                   E(X) = \frac{1}{(x+1)*(x+2)} = \frac{1}{(x+1)} - \frac{1}{(x+2)} \\\\= \frac{1}{(1)} - \frac{1}{(2)}\\\\= \frac{1}{(2)} - \frac{1}{(3)} \\\\=  \frac{1}{(3)} - \frac{1}{(4)}\\\\= ............................................\\\\=  \frac{1}{(n)} - \frac{1}{(n+1)}\\\\=  \frac{1}{(n+1)} - \frac{1}{(n+ 2)}

                   E(X) = Limit n->∞ [1 - 1 / ( n + 2 ) ]  

                   E(X) = 1

8 0
3 years ago
Can someone help me please
aleksklad [387]

9514 1404 393

Answer:

 IS a parallelogram

Step-by-step explanation:

The slope formula for the slope of the line between points (x1, y1) and (x2, y2) is ...

  m = (y2 -y1)/(x2 -x1)

The distance formula for the length of that same line is ...

  d = √((x2 -x1)^2 +(y2 -y1)^2)

Here, you're asked to use each of these formulas 4 times, once for each side of the quadrilateral. I find it convenient to let a calculator or spreadsheet do the repetitive calculations. The result is attached.

The attachment shows that opposites sides have the same length and slope, so are parallel. The quadrilateral is a parallelogram. (The two points used in each calculation are the ones on the result line and the line immediately below. That is why point B is copied to the end of the list.)

_____

<em>Additional comments</em>

There are much simpler ways to prove the figure is a parallelogram. My favorite is to add the coordinates of the end points of the diagonals:

  B +D = (-2+6, -9-3) = (4, -12)

  C +E = (0+4, -5-7) = (4, -12)

These values being the same demonstrates the midpoints of the diagonals are coincident. That will only be the case if the quadrilateral is a parallelogram.

__

If you must use slope and distance formulas, showing either pair of opposite sides is parallel and have the same length is sufficient to guarantee that the other two sides are also parallel and have the same length. That is, the calculations required in this problem only need to be applied to one pair of opposite sides. (Using a spreadsheet, it's not a lot of extra work to do the calculations for both pairs of opposite sides.)

7 0
3 years ago
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