Question 11
1 answer:
Answer:
D. would be my first answer, but make sure it's not a trick question. The answer could possibly be A. 0
Explanation:
Since we are choosing from the entire highschool, we know that our denomination should be 1500, which is the total number of students in the school.
Furthermore, if we want to select either a student with a music or art elective, then there are 385 students with art electives and 365 students with music electives.
So, we just add them up and divide by the total number:
=
as the probability.
Note: I'm not sure if it was a trick question though. The questions asks for the probability that a student chose both an art and a music elective, which is impossible because "each student chooses an elective," not multiple.
In this case, the answer would be 0.
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Answer: Part A. The IQR for town A is 4.5 and the IQR for town B is 4.5
Part B. No, they are assymetric.
Explanation: To find the interquatile range (IQR) of each set of data, you can do as follows:
1) Put the number in each set of data in order:
A: 3 4 5 5 6 7 8 9 9 20
B: 3 3 5 5 6 8 8 9 9
2) Find the median of each town data:
For A, the median is the number 6. Coincidently, the same can be said for town B: its median is 6.
3) Find Q1, which is the median (or the middle term) of the left side of the median:
A: 3 4 5 5 (set of numbers to calculate)
B: 3 3 5 5
Now, as both set of number are even, to find the median, we have to calculate the mean of the two central numbers:
For A: Q1 = = 4.5
For B: Q1 = = 4
4) Find Q3, which is the median of the right side of the first median:
A: 7 9 9 20 (set of numbers to calculate)
B: 8 8 9 9
As before, the median will be the mean:
For A: Q3 = = 9
For B: Q3 = = 8.5
5) The IQR is the result of a subtraction:
IQR = Q3 - Q1
For A: IQR = 4.5
For B: IQR = 4.5
For the two sets of data the IQR is the same and equals 4.5.
Part B: Box plot is a type of graphic, similar to histogram. To plot it, you need 5 points but for this question, it will be analised just the symmetric aspect. As the graphic is a retangule, to be symmetric, the median or mean has to be in the center of the retangule. In the case of the towns, the box plots are assymetric because the median of each town is closer to the Q1 of each town. In other words, the retangule is not "divided" exactly in half.