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garik1379 [7]
3 years ago
14

Write an equation in slope-intercept form for the line with slope 1/4 and y-intercept -5. Then graph the line.

Mathematics
1 answer:
Natalka [10]3 years ago
7 0

Formula: y=mx+b

Plug in your numbers. Y=1/4x-5

1/4 is the slope so it takes the place of m, and our y-intercept is -5 so it replaces b.

I can't put a graph on here, but go on desmos.com and put the equation in and it graphs it for you ;)

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Given the expression: 5x^10-80x^2 Part A: Rewrite the expression by factoring out the greatest common factor
Jlenok [28]

Answer:

A) 5x²(x^(8) - 16)

B) 5x²[(x⁴ + √16) • (x² + ∜16) • (x + (8√16) • (x - (8√16))]

Step-by-step explanation:

We are given the expression;

5x^(10) - 80x²

A) Since the expression is, 5x^(10) - 80x², the greatest common factor is 5x². So we will factorize that out.

So, we have;

5x²(x^(8) - 16)

B) The complete factorization of 5x²(x^(8) - 16) will be;

5x²[(x⁴ + √16) • (x⁴ - √16)]

Now, (x⁴ - √16)] can be broken than further into;

(x² + ∜16) • (x² - ∜16)

Also, (x² - ∜16) can be broken down into;

[(x + (8√16) • (x - (8√16))

So, our complete factorization gives us;

5x²[(x⁴ + √16) • (x² + ∜16) • (x + (8√16) • (x - (8√16))]

5 0
3 years ago
Please solve and explain how. Photo attached
geniusboy [140]

Answer:

Step-by-step explanation:

\frac{2}{k^2-2k}=1-\frac{1}{k^2-2k}

multiply by \frac{k^2-2k}{1} on each side

2=k^2-2k-1

add 1 on both sides 3=k^2-2k

make it equal 0

0=k^2-2k-3

Factor

(k-3)(k+1)

answer is 3 and -1

7 0
3 years ago
Diana put $8000 in a 10-year CDpaying 5% interest compoundedmonthly. After 2 years, shewithdrew all her money, and as anearly wi
Svet_ta [14]

Answer:

$8,430.23

Explanation:

From the statement of the problem:

• The principal amount = $8,000

,

• Interest Rate = 5%

,

• Compounding Period = 12 (Monthly)

The compound interest formula is given as:

A(n)=P\left(1+\frac{r}{k}\right)^{nk}

Using the compound period formula, we first, calculate the amount in her account at the end of 1 year.

\begin{gathered} A(1)=8000\left(1+\frac{0.05}{12}\right)^{12\times1} \\ A(1)=\$8409.30 \end{gathered}

This means that the interest she made during the first year is:

\text{ Interest during the first year}=8409.30-8000=\$409.30

Next, calculate the amount in her account at the end of the second year.

\begin{gathered} A(2)=8000\left(1+\frac{0.05}{12}\right)^{12\times2} \\ A(2)=\$8839.53 \end{gathered}

Since she paid back all the interest she made during the first year, the amount Diana was left with is:

\begin{gathered} 8839.53-409.30 \\ =8,430.23 \end{gathered}

Diana was left with $8,430.23.

6 0
1 year ago
I need help badly please help ​
Alina [70]

(4x³-5x²-2x+11)/(x+1)

[(x+1)(4x²-9x+7)]/(x+1) + 4/(x+1)

4x²-9x+7 + 4/(x+1)

4 0
3 years ago
Farfalla kites owns 3 factories around the globe. In one year, the original factory can make 600 kites, and each of the other fa
statuscvo [17]

Farfalla produces 2,400 kites every year.

The number of factories Farfalla owns around the globe = 3;

The number of kites produced by original factory every year = 600;

The number of kites produced by each of other 2 factories every year = 900;

Then the total kites produced by both other factories will be = 2 × 900 = 1800;

Now, the number of kites Farfalla produces every year is = 600 + 1800 = 2400;

To learn more about this, visit: brainly.com/question/8632760

#SPJ9

4 0
2 years ago
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