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Semmy [17]
3 years ago
14

Find ratios equivalent to the ratio described in the situation 1 to 6

Mathematics
1 answer:
katrin2010 [14]3 years ago
4 0
2/12, 4/24, 3/18, 5/30 etc.
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the total cost for two items is $19 is the difference in the cost of the two items is $5 find the cost of each item.
lora16 [44]

Ok so you spent 19 dollars the difference between prices is 5 dollars and your answer would be 12 and 7. If you need any help let me know.

5 0
3 years ago
Read 2 more answers
List all partitions of the set. (a) (1,2) (b) [a, b,c)
Alchen [17]

Answer: Hello mate!

The partition of a set is defined as a partition of the set into a nonempty subset, where the set itself is a subset of himself, then the set is a partition of himself.

a) in this we have a set of two objects; A = (1,2) the partitions of this set are: (∅), (1), (2) and (1,2). Where (∅) is the null set.

b) Now we have a set of three objects; B = (a,b,c) the partitions of this set are: (∅), (a), (b), (c), (a,b), (a,c), (b,c), (a,b,c)

3 0
3 years ago
Olivia picked 256 strawberries from the orchards fields. she divided the strawberries evenly into 6 baskets. how many strawberri
Fofino [41]

Answer:

42 strawberries are in each basket. 4 strawberries are left over.

Step-by-step explanation:

To find out how many she put into each basket, you need to divide 256/6. Your answer should 42.6666667. Round down to 42.

To find out how many are left over, multiply 42 x 6. You need to do this to figure out how many strawberries total she used trying to put them evenly into the baskets. Your answer should be 252. Then, you subtract 256 - 252. You do this to find out how many are left over. Your answer is 4.

5 0
3 years ago
Solve for W <br><br> T= sqrt(5/(wc)
Gnoma [55]
T= sqrt(5/wc) remove ( ) T= 5sqrt/wc multiply by wc Twc=5sqrt divide by Tc W= 5sqrt/cT hope this helps
5 0
3 years ago
Read 2 more answers
Water whose temperature is at 100∘C is left to cool in a room where the temperature is 60∘C. After 3 minutes, the water temperat
Tju [1.3M]

Answer:

21.68 minutes ≈ 21.7 minutes

Step-by-step explanation:

Given:

T=60+40e^{kt}

Initial temperature

T = 100°C

Final temperature = 60°C

Temperature after (t = 3 minutes) = 90°C

Now,

using the given equation

T=60+40e^{kt}

at T = 90°C and  t = 3 minutes

90=60+40e^{k(3)}

30=40e^{3k}

or

e^{3k}=\frac{3}{4}

taking the natural log both sides, we get

3k = \ln(\frac{3}{4})

or

3k = -0.2876

or

k = -0.09589

Therefore,

substituting k in 1 for time at temperature, T = 65°C

65=60+40e^{( -0.09589)t}

or

5=40e^{( -0.09589)t}

or

e^{( -0.09589)t}=\frac{5}{40}

or

e^{( -0.09589)t}=0.125

taking the natural log both the sides, we get

( -0.09589)t = ln(0.125)

or

( -0.09589)t = -2.0794

or

t = 21.68 minutes ≈ 21.7 minutes

6 0
3 years ago
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