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alexandr402 [8]
3 years ago
6

HELP PLEASE!!!!!!!!!!!

Mathematics
1 answer:
sashaice [31]3 years ago
3 0
The simplified expression should be 3/7
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Which weights more 2.48 or 2.5​
Mazyrski [523]
2.5 weighs more. It’s a greater number than 2.48
6 0
2 years ago
Graph the system of equations on your graph paper to answer the question.
scZoUnD [109]
<span>y=x-4
y=-x+6 
---------------------
Substitute x - 4 for y in </span>y=-x+6 
x-4=-x+6<span>
--------------------------------
Add X on each side
</span><span>x-4+x</span>=-<span>x+6+x
</span>2x - 4 = 6
--------------------------------------
Add 4 on each side
<span>2x-4+4</span>=<span>6+4
</span>2x = 10
------------------------------------------------
Divide by 2 on each side
2x ÷ 2 = 10 ÷ 2
x = 5
Now we have X
================================================================
To find Y we substitute 5 for x in y=<span>x-<span>4
</span></span>y = 5 - 4
y = 1
-----------------------------------------------------
Your answers are Y = 1 and X = 5

8 0
2 years ago
Solve the following new equation
mixer [17]

Answer:

<h3>x = 1.54 or x = - 4.54 to 2 decimal places</h3>

Step-by-step explanation:

x² + 3x - 7 = 0

Using the quadratic formula

a = 1 b = 3 c = - 7

x =  \frac{3 ± \sqrt{ {3}^{2} - 4(1)( - 7) }  }{2(1)}  \\  x =  \frac{ - 3± \sqrt{9 + 28} }{2}  \\  \\ x =  \frac{ -3 ± \sqrt{37} }{2}  \\  \\ x =  \frac{ - 3 +  \sqrt{37} }{2}  \:  \:  \:  \:  \: or \:  \:  \: x =  \frac{ - 3 -  \sqrt{37} }{2}  \\  \\ x = 1.54 \:  \:  \: or \:  \: x =  - 4.54

Hope this helps you

7 0
3 years ago
These 2 questions are worth 35 points for the brainliest user. If you answer these two questions, I will answer any of yours for
elixir [45]

Answer:

1. 6,8,10

Step-by-step explanation:

1. 6,8,10

2. Scalene Triangle

4 0
3 years ago
Read 2 more answers
(10 pts) (a) (2 pts) What is the difference between an ordinary differential equation and an initial value problem? (b) (2 pts)
laiz [17]

Answer:

Step-by-step explanation:

(A) The difference between an ordinary differential equation and an initial value problem is that an initial value problem is a differential equation which has condition(s) for optimization, such as a given value of the function at some point in the domain.

(B) The difference between a particular solution and a general solution to an equation is that a particular solution is any specific figure that can satisfy the equation while a general solution is a statement that comprises all particular solutions of the equation.

(C) Example of a second order linear ODE:

M(t)Y"(t) + N(t)Y'(t) + O(t)Y(t) = K(t)

The equation will be homogeneous if K(t)=0 and heterogeneous if K(t)\neq 0

Example of a second order nonlinear ODE:

Y=-3K(Y){2}

(D) Example of a nonlinear fourth order ODE:

K^4(x) - \beta f [x, k(x)] = 0

4 0
3 years ago
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