2.5 weighs more. It’s a greater number than 2.48
<span>y=x-4
y=-x+6
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Substitute x - 4 for y in </span>y=-x+6
x-4=-x+6<span>
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Add X on each side
</span><span>x-4+x</span>=-<span>x+6+x
</span>2x - 4 = 6
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Add 4 on each side
<span>2x-4+4</span>=<span>6+4
</span>2x = 10
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Divide by 2 on each side
2x ÷ 2 = 10 ÷ 2
x = 5
Now we have X
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To find Y we substitute 5 for x in y=<span>x-<span>4
</span></span>y = 5 - 4
y = 1
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Your answers are Y = 1 and X = 5
Answer:
<h3>x = 1.54 or x = - 4.54 to 2 decimal places</h3>
Step-by-step explanation:
x² + 3x - 7 = 0
Using the quadratic formula
a = 1 b = 3 c = - 7

Hope this helps you
Answer:
1. 6,8,10
Step-by-step explanation:
1. 6,8,10
2. Scalene Triangle
Answer:
Step-by-step explanation:
(A) The difference between an ordinary differential equation and an initial value problem is that an initial value problem is a differential equation which has condition(s) for optimization, such as a given value of the function at some point in the domain.
(B) The difference between a particular solution and a general solution to an equation is that a particular solution is any specific figure that can satisfy the equation while a general solution is a statement that comprises all particular solutions of the equation.
(C) Example of a second order linear ODE:
M(t)Y"(t) + N(t)Y'(t) + O(t)Y(t) = K(t)
The equation will be homogeneous if K(t)=0 and heterogeneous if 
Example of a second order nonlinear ODE:

(D) Example of a nonlinear fourth order ODE:
![K^4(x) - \beta f [x, k(x)] = 0](https://tex.z-dn.net/?f=K%5E4%28x%29%20-%20%5Cbeta%20f%20%5Bx%2C%20k%28x%29%5D%20%3D%200)