Answer:
Isn't confined. It is a term created by Jack Welch. Boundaryless organization is a term coined by Jack Welch during his tenure as CEO of GE; it refers to an organization that eliminates traditional barriers between departments as well as barriers between the organization and the external environment
Step-by-step explanation:
A boundaryless organization is a contemporary approach in organizational design. In a boundaryless organization, the boundaries that divide employees such as hierarchy, job function, and geography as well as those that distance companies from suppliers and customers are broken down.
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The half-life of the element is 13 minutes, which means after 13 minutes, any starting amount decays to half. So element X decays with a rate k such that
![\dfrac12 = e^{13k}](https://tex.z-dn.net/?f=%5Cdfrac12%20%3D%20e%5E%7B13k%7D)
Solve for k :
![\ln\left(\dfrac12\right) = \ln\left(e^{13k}\right)](https://tex.z-dn.net/?f=%5Cln%5Cleft%28%5Cdfrac12%5Cright%29%20%3D%20%5Cln%5Cleft%28e%5E%7B13k%7D%5Cright%29)
![-\ln(2) = 13k \ln(e)](https://tex.z-dn.net/?f=-%5Cln%282%29%20%3D%2013k%20%5Cln%28e%29)
![-\ln(2) = 13k](https://tex.z-dn.net/?f=-%5Cln%282%29%20%3D%2013k)
![\implies k = -\dfrac{\ln(2)}{13}](https://tex.z-dn.net/?f=%5Cimplies%20k%20%3D%20-%5Cdfrac%7B%5Cln%282%29%7D%7B13%7D)
Now, we solve for t such that
![36 = 710e^{kt}](https://tex.z-dn.net/?f=36%20%3D%20710e%5E%7Bkt%7D)
![e^{kt} = \dfrac{18}{355}](https://tex.z-dn.net/?f=e%5E%7Bkt%7D%20%3D%20%5Cdfrac%7B18%7D%7B355%7D)
![\ln\left(e^{kt}\right) = \ln\left(\dfrac{18}{355}\right)](https://tex.z-dn.net/?f=%5Cln%5Cleft%28e%5E%7Bkt%7D%5Cright%29%20%3D%20%5Cln%5Cleft%28%5Cdfrac%7B18%7D%7B355%7D%5Cright%29)
![kt = \ln\left(\dfrac{18}{355}\right)](https://tex.z-dn.net/?f=kt%20%3D%20%5Cln%5Cleft%28%5Cdfrac%7B18%7D%7B355%7D%5Cright%29)
![-\dfrac{\ln(2)}{13} t = \ln\left(\dfrac{18}{355}\right)](https://tex.z-dn.net/?f=-%5Cdfrac%7B%5Cln%282%29%7D%7B13%7D%20t%20%3D%20%5Cln%5Cleft%28%5Cdfrac%7B18%7D%7B355%7D%5Cright%29)
![\implies t = -\dfrac{13 \ln\left(\frac{18}{355}\right)}{\ln(2)}](https://tex.z-dn.net/?f=%5Cimplies%20t%20%3D%20-%5Cdfrac%7B13%20%5Cln%5Cleft%28%5Cfrac%7B18%7D%7B355%7D%5Cright%29%7D%7B%5Cln%282%29%7D)
![\implies t = -13 \log_2\left(\dfrac{18}{355}\right) \approx \boxed{55.9}](https://tex.z-dn.net/?f=%5Cimplies%20t%20%3D%20-13%20%5Clog_2%5Cleft%28%5Cdfrac%7B18%7D%7B355%7D%5Cright%29%20%5Capprox%20%5Cboxed%7B55.9%7D)
Answer:
They can make 10 different groups of three.
Step-by-step explanation:
The order in which the people are in the car is not important, so we use the combinations formula to solve this question.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.
![C_{n,x} = \frac{n!}{x!(n-x)!}](https://tex.z-dn.net/?f=C_%7Bn%2Cx%7D%20%3D%20%5Cfrac%7Bn%21%7D%7Bx%21%28n-x%29%21%7D)
How many different groups of three can the five of them make?
Combinations of 3 from a set of 5. So
![C_{5,3} = \frac{5!}{3!(5-3)!} = 10](https://tex.z-dn.net/?f=C_%7B5%2C3%7D%20%3D%20%5Cfrac%7B5%21%7D%7B3%21%285-3%29%21%7D%20%3D%2010)
They can make 10 different groups of three.
Answer:
![13 \frac{1}{3} c - 1 \frac{1}{2}](https://tex.z-dn.net/?f=13%20%5Cfrac%7B1%7D%7B3%7D%20c%20-%201%20%5Cfrac%7B1%7D%7B2%7D%20)
Step-by-step explanation:
We want to combine alike terms so
-2/3c+14c & -9/5+3/10
14c-2/3
![\frac{14}{1} c - \frac{2}{3} c](https://tex.z-dn.net/?f=%20%5Cfrac%7B14%7D%7B1%7D%20c%20-%20%20%5Cfrac%7B2%7D%7B3%7D%20c)
Multiply 14/1 by 3/3 to get the denominators the same
![\frac{42}{3} c - \frac{2}{3} c](https://tex.z-dn.net/?f=%20%5Cfrac%7B42%7D%7B3%7D%20c%20-%20%20%5Cfrac%7B2%7D%7B3%7D%20c)
Subtract
![\frac{40}{3} c](https://tex.z-dn.net/?f=%20%5Cfrac%7B40%7D%7B3%7D%20c)
simplify
![13 \frac{1}{3} c](https://tex.z-dn.net/?f=13%20%5Cfrac%7B1%7D%7B3%7D%20c)
now
![\frac{3}{10} - \frac{9}{5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B10%7D%20%20-%20%20%5Cfrac%7B9%7D%7B5%7D%20)
Multiply 9/5 by 2/2
![\frac{3}{10} - \frac{ 18}{10}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B10%7D%20%20-%20%20%5Cfrac%7B%2018%7D%7B10%7D%20)
Subtract
![- \frac{15}{10}](https://tex.z-dn.net/?f=%20%20-%20%5Cfrac%7B15%7D%7B10%7D%20)
Simplify
![- 1 \frac{1}{2}](https://tex.z-dn.net/?f=%20-%201%20%5Cfrac%7B1%7D%7B2%7D%20)
put both together
![13 \frac{1}{3}c - 1 \frac{1}{2}](https://tex.z-dn.net/?f=13%20%5Cfrac%7B1%7D%7B3%7Dc%20%20-%201%20%5Cfrac%7B1%7D%7B2%7D%20)
Hope this helps! If you have any questions on how I got my answer feel free to ask. Stay safe!