Answer:
Step-by-step explanation:
x = days, y = minutes
first day, she walked for 10 minutes......(1,10)
2nd day, she walked for 15 minutes.....(2,15)
now, we find the slope...
(1,10) , (2,15)
slope = (y2 - y1) / (x2 - x1) = (15 - 10) / (2 - 1) = 5/1 = 5
now we use y = mx + b.....we are looking for b, the y int
y = mx + b
slope(m) = 5
u can use either set of points...(1,10)...x = 1 and y = 10
now we sub and find b
10 = 5(1) + b
10 = 5 + b
10 - 5 = b
5 = b
so this equation is y = 5x + 5
so to calculate the number of minutes she walked on day 20, sub in 20 for x and solve for y
y = 5x + 5
y = 5(20) + 5
y = 100 + 5
y = 105 <=== she walked for 105 minutes
Answer:
-528
Step-by-step explanation:
44*4=176
44*7=308
176-308=-132
-132*4=-528
My answer is X=5/4 or X=-11/4, hopes it can help you~
Answer:
C. 10
Step-by-step explanation:
Let x and y represent push-ups and pull-ups, respectively.
x + y = 24 . . . . . . combined total of push/pull-ups
2x +4y = 68 . . . . time required for the exercise
We can divide the second equation by 2 and subtract the first:
(1/2)(2x +4y) -(x +y) = (1/2)(68) -(24)
x +2y -x -y = 34 -24 . . . . . eliminate parentheses
y = 10 . . . . . . . . . simplify
Malia did 10 pull-ups.
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She did 14 push-ups.
It would be 12x-3y because 10 + 2 is 12