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Ivahew [28]
2 years ago
8

Basically everything is in the picture PLEASE HELP me ASAP​

Mathematics
1 answer:
Ugo [173]2 years ago
6 0

Answer:

A = 89.1327

Step-by-step explanation:

1. Approach

To solve this problem, one must divide the figure up into two smaller figures. Calculate the areas of these smaller figures, and then finally, add up the result. The given figure can be divided into a square and a semi-circle. One can solve for the area of the square using the formula (length*width=area). One can solve for the area of the semicircle by solving for the area of the circle, and then dividing it by (2).

2. Solve for the area of the square

This is the easier part, all one has to do is multiply the length of the square by the width;

length * width = area\\\\8 * 8 = area\\\\64 = area

3. Solve for the area of the semi-circle

The formula for the area of a circle is;

(pi)r^2=A

Where coefficient (pi) represent the values (3.1415...), parameter (r) represent the radius of the circle, and (A) represents the area.

In the problem, one is given the diameter of the semicircle. The diameter is the largest cord (a line that is drawn in a circle) in the circle, this cord will pass through the center of the circle. The radius is the distance from the center of the circle to the outer edge of the circle. The radius, by its definition will always be half of the diameter. It is given that the diameter of the given circle is (8), therefore the radius is (4), because (8÷2=4).

Substitute in the values and solve;

(pi)(4)^2 = A\\\\3.1415*(16)=A\\\\50.2655=A

Don't forget to divide this in half, because the given figure is a semi-circle, not a circle;

25.1327

4. Putting it together

Now add the value for the area of the semi-circle, with the value for the area of the square;

square + semi-circle = Total\ area\\\\64 + 25.1327 = Total\ area\\\\89.1327 = Total\ area

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galben [10]
Hey. Let me help you on this one.

In order for us to solve this problem easier, let's break it apart. We can also graph the triangle so we get visual of this problem.

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Let's form a SOHCAHTOA function which you have probably already learned in your Geometry course.

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timurjin [86]

Answer:

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