Answer:
Step-by-step explanation:
a.6/1/2=x
b. 12
Answer:
c = -10
Step-by-step explanation:
16c -24=4c -144
Subtract 4c from both sides
16c - 4c - 24 = 4c - 4c - 144
12c - 24 = -144
Add 24 to both sides
12c -24 + 24 = -144 + 24
12c = -120
Note: -144 + 24 = -120
12c = -120
Divide both sides by 12
12c/12 = -120/12
c = -10
Note: 12/12 = 1 and -120/12 = -10
Checking :
16c -24=4c -144
Put c = -10
16(-10) - 24 = 4(-10) - 144
-160 - 24 = -40 - 144
-184 = -184
Therefore
c = -10
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Answer:
Ground speed = 131.25 km/h
Bearing = 92.68º
Step-by-step explanation:
If we imagine a triangle to depict the question with one side 134 km/h at an angle of 78º to the right of vertical (the plane's speed vector).
At the end, we have a line 21 km/h at an angle of 180 (from north), a vertical down from the end of the plane's vector. This vertex is angle B
This makes a triangle with the interior angle B of 78º.
The 3rd side is the ground speed which we can find using the Cosine rule:
b² = a² + c² - 2•a•c•cos(78)
b² = 134² + 21² - 2•134•21•cos(78)
b² = 17226.873
b = 131.25 km/h
The true course bearing" is the ground track. Thus;
Using the Sine rule to find angle A, we have;
(sin(A))/34= sin(78)/b
Thus,
sin(A) = (34 x sin(78))/131.25
sin(A) = 0.2534
A = sin^(-1)0.2534
A = 14.68º
Ground track = A + 78 = 14.68 + 78 = 92.68º
Answer:
160
Step-by-step explanation:
total = 100%
we know,
55 % of total = 88
or, 55/100 * total = 88
so total = 160
3x-5y=13
(-3) (x-2y=5) = -3x+2y=-15
3x-5y=13
+
-3x+2y=-15
-3y=-2
Answer = y=2/3